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DerKrebs [107]
3 years ago
13

A 10.0-L vessel contains gas A at a pressure of 300.0 torr. Gas A is forced into the second 3.00-L vessel. Calculate the resulti

ng pressure in torr. Assume the temperature remains constant
Chemistry
1 answer:
barxatty [35]3 years ago
4 0

Answer:

1.50 x 10^2

Explanation:

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Which of the following is a salt
poizon [28]

Answer: NaCl; Sodium Chloride

Explanation:

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3 years ago
What is an alloy?<br> Answer question 2 if you want.
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Answer:

An alloy is a combination of metals or metals combined with one or more other elements. For example, combining the metallic elements gold and copper produces red gold, gold and silver becomes white gold, and silver combined with copper produces sterling silver. Elemental iron, combined with non-

Explanation:

that's what an alloy is all the rocks including gold silver combined with copper  and sterling silver

7 0
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A 4 gram metal is heated and it's temperature changes from 25 degrees C to 35
mote1985 [20]

Answer:

O60J

Explanation:

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3 years ago
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What is the mass percent concentration of a solution containing 29.0 g NaCl and 115.0 mL of water? Assume a density of 1.00 g/mL
marin [14]

Answer:

Mass percent concentration: 25,2% m/m

Explanation:

The percentage mass by mass indicates the grams of solute in 100 grams of solution. We convert the ml of water into g from the density formula:

δ= m/v    m=δx v= 1 g/ml x 115 ml= 115 g

115g solution-----29 g NaCl

100g solution----x=(100g solutionx29 g NaCl)/115g solution

x=25,2173913 g NaCl

5 0
3 years ago
Calculate the total amount of energy required in calories to convert 50.0 g of ice at 0.00 degrees Celsius to steam at 100. degr
r-ruslan [8.4K]

Answer:

HFusion*mass + Spec.Heat*mass*ΔT + HVap*mass

80cal/g*50.0g + 1.00cal/g°C*50.0g*(100°C-0°C) + 540cal/g*50g

3.60x10⁵cal

Explanation:

Using the HFusion we can find the heat needed to convert the ice to liquid water.

With specific heat capacity we can find the heat needed to increase the temperature of water from 0 to 100°C.

With HVap we can find the heat to convert the liquid water into steam.

The equations are:

<h3>HFusion*mass + Spec.Heat*mass*ΔT + HVap*mass</h3><h3 />

Computing the values:

<h3>80cal/g*50.0g + 1.00cal/g°C*50.0g*(100°C-0°C) + 540cal/g*50g</h3>

36000cal =

<h3>3.60x10⁵cal</h3>
8 0
3 years ago
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