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ELEN [110]
2 years ago
12

Write the formula for diphosphorous pentoxide

Chemistry
1 answer:
ehidna [41]2 years ago
7 0

Answer:

P4O10

Explanation:

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What carries electric current from the cell to the other components of a circuit.​
Rasek [7]

Answer:

The different objects that make up a circuit are called components. A circuit must have a power source, such as a battery, and the current flows through a conductor, such as a wire.

Explanation:

I hope that was useful.

3 0
3 years ago
The decomposition of nitrogen dioxide is described by the following chemical equation:
kow [346]

Answer:

The balanced chemical equation will be "NO_{2}+O\rightarrow NO+O_{2}".

Explanation:

The given equation is:

2NO_{2}\rightarrow 2NO+O_{2}

<u>Step 1:</u>

<u></u>2NO_{2}\rightarrow NO+O...(equation 1)

<u>Step 2:</u>

<u></u>NO_{2}+O\rightarrow NO+O_{2}...(equation 2)

On adding "equation 1" and "equation 2", we get

⇒  NO_{2}+NO_{2}+O\rightarrow NO+O+NO+O_{2}

⇒  2NO_{2}\rightarrow 2NO+O_{2}

The second step:

⇒  NO_{2}+O\rightarrow NO+O_{2}

3 0
3 years ago
How many atoms are in 10.0 moles of titanium
Tema [17]
The answer should be 479 i could possibly be wrong but that’s what i got because one mole is 47.90 grams
8 0
2 years ago
a compound has 15.39 g of gold for every 2.77 g of chlorine. simplified there is _____ g of gold for every 1 g of chlorine
iren [92.7K]

Answer:

There is 5.56 g of gold for every 1 g of chlorine

Explanation:

The ratio is the relationship between two numbers, defined as the ratio of one number to the other. So, the ratio between two numbers a and b is the fraction \frac{a}{b}

You know that a compound has 15.39 g of gold for every 2.77 g of chlorine. This can be expressed by the ratio:

\frac{15.39 g  of gold}{2.77 g of chlorine}

The proportion is the equal relationship that exists between two reasons and is represented by:    \frac{a}{b}=\frac{c}{d}

This reads a is a b as c is a d.

To calculate the amount of gold per 1 g of chlorine, the following proportion is expressed:

\frac{15.39 g  of gold}{2.77 g of chlorine}=\frac{mass of gold}{1 g of chlorine}

Solving for the mass of gold gives:

mass of gold=1 g of chlorine*\frac{15.39 g  of gold}{2.77 g of chlorine}

mass of gold= 5.56 grams

So, <u><em>there is 5.56 g of gold for every 1 g of chlorine</em></u>

5 0
3 years ago
25cm3 of 0.2mol/dm3 barium hydroxide solution reacted with 22.8cm3 hydrochloric acid. Calculate the concentration of the hydroch
AVprozaik [17]

Explanation:

1 mol of Ba(OH)2 = 2 moles of HCl

7 0
3 years ago
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