A solution of diamminesilver(I) chloride is treated with dilute nitric acid. What products you get? [Ag(NH3)2]Cl(aq) + HNO3(aq)
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Answer:
Explanation:
Given :
Mass of a bar of lead = 115.2 g
Initial water level = 25 mL
Final water level = 35.5 mL
Difference in the water level = 35.5 - 25
= 10.5 mL
=
We know that when a body is submerged in water, it displaces its own volume of water.
Therefore, the volume of the lead bar = volume of the water displaced = 10.5 mL =
We know that mathematically, density is the ratio of mass of body to its volume.
Density of the lead bar is given by :
=