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Studentka2010 [4]
4 years ago
14

Oxidation Inhibitors are antioxidant additives that slow the degradation

Engineering
1 answer:
Tcecarenko [31]4 years ago
5 0

Answer: True

Explanation:

Oil oxidation is a process that all oil goes through and involves a series of chemical reactions between compounds in the oil and oxygen that lead to the quality of the oxygen falling. In other words, oxidation degrades oil.

Even though this is a process that all oil goes through and one that cannot be stopped, it's pace can be reduced. One way of doing this is by adding oxidation inhibitors which are antioxidant additives that work to slow the degradation  of the oil stock by oxidation.

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Water from a stationary nozzle impinges on a moving vane with turning angle θ = 120. The vane moves away from the nozzle with co
Tems11 [23]

Answer:

The force that must be applied to maintain the vane speed constant is 2771.26 N

Explanation:

Given;

turning angle of the vane = 120°

control volume velocity, u = 10 m/s

absolute velocity, v = 30 m/s

nozzle area = 0.004 m²

The force acting on the vane has horizontal and vertical components:

Based on Reynolds general control volume system;

The horizontal force component of the system, ∑Fₓ = ρW²A(1-cosθ)

where;

ρ is the density of water = 1000 kg/m³

W is the relative velocity = Absolute velocity - control volume velocity

W = v - u

    = 30 - 10 = 20m/s

∑Fₓ = ρW²A(1-cosθ) = 1000 x 20² x 0.004 (1 - cos 120) = 2400 N

The vertical force component of the system, ∑Fy = ρW²A(sinθ)

∑Fy = ρW²A(sinθ) = 1000 x 20² x 0.004 x sin(120) = 1385.6 N

The magnitude of the force applied = \sqrt{F_x^2 + F_y^2}

F = \sqrt{2400^2 + 1385.6^2} = 2771.26 \ N

The force that must be applied to maintain the vane speed constant is 2771.26 N

6 0
3 years ago
Read 2 more answers
This is just so I can flip the picture
Pepsi [2]

Answer:

ok

Explanation:

thx for points

7 0
4 years ago
Need the answer now- English<br>kailangan ang sagot ngayon-tagalog<br><br>mag practice tayo!<br>​
pychu [463]

Answer:

heirjfurifbhdnrgskeviebreo

7 0
3 years ago
Create a file named students containing the following data in your current directory. Each line in this file represents a studen
Ostrovityanka [42]

Answer:

#!/bin/bash

# Simple line count example, using bash

# Usage: ./line_count.sh file

# -----------------------------------------------------------------------------

# Link filedescriptor 10 with stdin

exec 10<&0

# stdin replaced with a file supplied as a first argument

exec < $1

# remember the name of the input file

in=$1

# init

file="current_line.txt"

let count=0

# this while loop iterates over all lines of the file

while read LINE

do

   # increase line counter  

   ((count++))

   # write current line to a tmp file with name $file (not needed for counting)

   echo $LINE > $file

   # this checks the return code of echo (not needed for writing; just for demo)

   if [ $? -ne 0 ]  

    then echo "Error in writing to file ${file}; check its permissions!"

   fi

done

echo "Number of lines: $count"

echo "The last line of the file is: `cat ${file}`"

# Note: You can achieve the same by just using the tool wc like this

echo "Expected number of lines: `wc -l $in`"

# restore stdin from filedescriptor 10

# and close filedescriptor 10

exec 0<&10 10<&-

Explanation:

4 0
4 years ago
A cylindrical rod of a metal alloy is stressed elastically in tension. The original diameter was 11 mm and a force of 55 kN was
andrey2020 [161]

Answer:

10.984mm

Explanation:

by elastic modulus

stress=modulus of elasticity*strain

stress=loading/area                          area" cross-section"

11mm=0.011m

area=π(d/2)^2=π(0.011/2)^2=9.503*10^-5 square meter

stress=55000/(9.503*10^-5)=578.745 MPa

convert MPa and GPa to pascal.

strain=stress/modulus=(578.745*10^6)/(125*10^9)=0.00463............axial strain

v=Poisson  ratio

lateral strain=(-v)*axial strain= -0.31*0.00463

lateral strain= -1.4353*10^-3=change in diameter/ original diameter

change in diameter=(-1.4353*10^-3)*0.011= -1.57883*10^-5 m

negative indicates decrease in diameter.

decrease in dia.=0.01578mm

new diameter=11-0.01578= 10.984mm

3 0
3 years ago
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