Steam at 320°C flows in a stainless steel pipe (k 5 15 W/m·K) whose inner and outer diameters are 5 cm and 5.5 cm, respectively.
The pipe is covered with 3-cm-thick glass wool insulation (k 5 0.038 W/m·K). Heat is lost to the surroundings at 5°C by natural convection and radiation, with a combined natural convection and radiation heat transfer coefficient of 15 W/m2 ·K. Taking the heat transfer coefficient inside the pipe to be 80 W/m2 ·K, determine the rate of heat loss from the steam per unit length of the pipe. Also determine the temperature drops across the pipe shell and the insulation.
1 answer:
Answer:
- determine the rate of heat loss from the steam per unit length of the pipe. = 93.94w
- Also determine the temperature drops across the pipe shell and the insulation = 290.18°C
Explanation:
- determine the rate of heat loss from the steam per unit length of the pipe. = 93.94w
- Also determine the temperature drops across the pipe shell and the insulation = 290.18°C
check the attached doc for proper explannation
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Answer:
This is self locking.
Explanation:
Given that
Diameter d= 40 mm
Pitch (P)= 6 mm
Torque T= 1 KN.m
Friction(μ) = 0.1
Thread is double square.
Condition for self locking
L= n x P
N= number of start
Here given that double start so n=2
L=2 x 6 = 12 mm
(μ = 0.1)
So from we can that this is self locking.
Answer:
F=989.6 N
Explanation:
Given that
Diameter of shaft = 70 mm
Diameter of bearing sleeve =70.2 mm
So clearance h=0.1 mm
Speed V= 400 mm/s
Length of shaft = 250 mm
We know that
μ= 900 x 0.005 Pa-s
μ= 4.5 Pa-s
As we know that
From Newton's law of viscosity ,the shear stress given as follows
We also know that
Force = shear stress x area
Now by putting the values
So force
F= 18,000 x π x 0.07 x 0.25
F=988.6 N