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pantera1 [17]
3 years ago
10

A rope attached to a load of 175 kg bricks Ilifts the bricks with a steady acceleration of 0.12.m/s^2 straight up. What is the t

ension in the rope? (a)2028N (b)1645 N (c) 1894 N (d) 1976 N (e) 1736 N (f) 1792 N

Physics
2 answers:
andrew-mc [135]3 years ago
4 0

Answer:

Tension, T = 1736 N

Explanation:

It is given that,

Mass of bricks, m = 175 kg

A rope is attached to a load of 175 kg bricks lifts the bricks with a steady acceleration of 0.12 m/s² in vertically upwards direction. let T is the tension in the rope. Using second equation of motion as :

T - mg = ma

T = ma + mg

T = m(a + g)

T = 175 kg ( 0.12 m/s² + 9.8 m/s² )

T = 1736 N

Hence, the tension in the wire is 1736 N.

Novosadov [1.4K]3 years ago
4 0

Answer:

The tension in the rope is 1736 N.

(e) is correct option.

Explanation:

Given that,

Mass of bricks = 175 kg

Acceleration = 0.12 m/s²

Let T is the tension in the rope.

A rope attached to a load of 175 kg bricks lifts the bricks with a steady acceleration of 0.12.m/s^2 in vertically upward direction.

Using equation of balance

T-mg=ma

T=mg+ma

T=175(9.8+0.12)

T= 1736\ N

Hence, The tension in the rope is 1736 N.

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A periodic transverse wave has an amplitude of 0.20 meter and a wavelength of 3.0 meters. If the frequency of this wave is 12 Hz
skelet666 [1.2K]

Answer:

36 m/s

Explanation:

The speed of wave is a product of wavelength and frequency, expressed as s=fw where f is frequency in Hz and w is wavelength. Wavelength is the distance between successive crests while frequency is also the reciprocal of time. Amplitude has no effect on the velocity of waves. Substituting frequency with 12 Hz and wavelength with 3 m then the speed will be

S=3*12=36 m/s

Therefore, the speed is 36 m/s

5 0
3 years ago
In a mattress test, you drop a 7.0 kg bowling ball from a height of 1.5 m above a mattress, which as a result compresses 15 cm a
Assoli18 [71]

Answer:

(c) 10.29 J

(d) 113.19 J

(e) 113.19 J

(f) 10061 N/m

Explanation:

15 cm = 0.15 m

Let g = 9.8 m/s2

(c) The work done by gravitational force is the product of gravity force and the distance compressed

E_p = mgx = 7*9.8*0.15 = 10.29 J

(d) By using law of energy conservation with potential energy reference being 0 at the maximum compression point. As the ball falls and come to a stop at the compression point, its potential energy is transferred to elastic energy, which is the work that the mattress does on the ball:

E_p = E_e

E_e = mgh

where h = 1.5 + 0.15 = 1.65 m is the vertical distance that it falls.

E_e = 7*9.8*1.65 = 113.19 J

(e) Before the compression, the potential energy of the mattress is 0. After the compression, the potential energy is 113.19J. So it has increased by 113.19J due to the potential energy transferred from the falling ball.

(f) E_e = 113.19 = kx^2/2

k0.15^2/2 = 113.19

k = 10061 N/m

8 0
3 years ago
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A 650 kg car accelerates at 4.0 m/s2 south. what is the net force acting on it?
Lelu [443]
Fnet=mass x acceleration 
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8 0
4 years ago
What are the units of work?
aleksandrvk [35]
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3 0
3 years ago
Select the correct answer.
Galina-37 [17]

Answer:

C) The densities of the samples are different, so a chemical reaction has occurred.

Explanation:

Given,

The volume of the sample A, v = 45 cm³

The mass of the sample A, m = 0.5 g

The volume of the sample B, v = 65 cm³

The mass of the sample B, m = 1.3 g

To find the whether there is a chemical reaction has occurred, first to examine the physical properties of the samples.

The color of the samples remains the same. This will not lead to valid result. The scientist need to examine further.

Next level is to check the densities of the substance.

The density of the Sample A

                                    ρₐ = 0.5/45

                                        = 0.011 g/cm³

The density of sample B

                                      ρₓ = 1.3/65

                                          = 0.02 g/cm³

On analyzing the densities of the samples, sample A is less denser than sample B.

Hence, a chemical reaction has occurred.

7 0
3 years ago
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