Which equation has a constant of proportionality equal to 3? A. y= 8/5 x B. y= 1/3 x C. y= 1/4 x D. y= 18/6 x PLEASE HELP ME :c

Mathematics

1 answer:

denis-greek [22]3 years ago

6 0

Answer:

(D) $y=\frac{18}{6}x$

Step-by-step explanation:

We will be able to know if an equation has a constant of proportionality of 3 if the constant which is being multiplied by x is equal to 3.

$\frac{8}{5} =1.6$ so no for A.

$\frac{1}{3} = 0.\overline{33}$ so no for B too.

$\frac{1}{4} = 0.25$ so no for C as well.

$\frac{18}{6} = 3$ , so D works.

Hope this helped!

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Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$