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Ksivusya [100]
3 years ago
7

Which equation has a constant of proportionality equal to 3? A. y= 8/5 x B. y= 1/3 x C. y= 1/4 x D. y= 18/6 x PLEASE HELP ME :c

Mathematics
1 answer:
denis-greek [22]3 years ago
6 0

Answer:

(D) y=\frac{18}{6}x

Step-by-step explanation:

We will be able to know if an equation has a constant of proportionality of 3 if the constant which is being multiplied by x is equal to 3.

\frac{8}{5} =1.6 so no for A.

\frac{1}{3} = 0.\overline{33} so no for B too.

\frac{1}{4} = 0.25 so no for C as well.

\frac{18}{6} = 3, so D works.

Hope this helped!

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Select the decimal that is equivalent to 13/75
leva [86]

I am not sure if you have any choices. Here are some options:

0.17333333333

This is also notated by .1733 with a line over the top of the two 3's indicating that these number continue repeating.

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3 years ago
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Write an inequality using variables x and y whose graph is described by the given information. The points (2,5) and (-3,-5) lie
luda_lava [24]

The inequality using variables x and y which satisfy the points are; y>-3x+3.

<h3>What is inequality?</h3>

Inequality is defined as the relation which makes a non-equal comparison between two given functions.

Given that the points (2,5) and (-3,-5) lie on the boundary line.

The system of inequality is given by:

y>-3x+3-

Now, the point that will lie in the solution set to the following system of inequality are the point that satisfies the inequality.

a)  (6, 5)

when x=6 and y= 5

then we have:

y>-3x+3

6 > -3×5 + 3

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This means that the point will lie in the solution set.

Also, (-2, -3) when x= -2 and y= -3

then we have:

5 > -3×(-2) + 3

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Hence, the inequality using variables x and y which satisfy the points are; y>-3x+3.

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8 0
1 year ago
Vertex = (2,5), Point (0, 1)
Rama09 [41]

Answer:

therefore y= - (x-2)^2 + 5

Step-by-step explanation:

u do this by using this format here ..,

y=a(x-h)^2+k

sub in the vertex points as h=2 and k = 5 , since the 2 is positive its sign will be -2 in the brackets because when solving for x-2=0 it is x=2

y=a(x-2)^2+5

then with your (0,1) points plug that in as y and x

1=a(0-2)^2+5

1=a(-2)^2+5

1=4a+5

1-5=4a

-4=4a

a=-1

therefore y= - (x-2)^2 + 5

8 0
3 years ago
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KATRIN_1 [288]

Answer:

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Step-by-step explanation:

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