The length of the rectangle is = 72 cm
The width of the rectangle is = 56 cm
Area of the rectangle is = 
= 
cm²
As given, the other rectangle has the same area as this one, but its width is 21 cm.
Let the length here be = x
Hence, length is 192 cm.
We can see that as width decreases, the length increases if area is constant and when length decreases then width increases if area is constant.
So, in the new rectangle,constant of variation=k is given by,
or 
Hence, the constant of variation is 
Answer: 
Step-by-step explanation:
We know that the standard quadratic equation is ax^2+bx+c=0
Let's compare all the given equation to it and , find discriminant.
1. a=2, b= -7, c=-9
So it has 2 real number solutions.
2. a=1, b=-4, c=4
So it has only 1 real number solution.
3. a=4, b=-3, c=-1
So it has 2 real number solutions.
4. a=1, b=-2, c=-8
So it has 2 real number solutions.
5. a=3, b=5, c=3
Thus it does not has real solutions.
Answer:
38 and 39
Step-by-step explanation:
Since the two integers are consecutive, then one is one larger than the other. Therefore, lets call them x and x+1. We can now set up the following equation:
x+(x+1)=77
2x+1=77
2x=76
x=38
x+1=39
Hope this helps!
<span>Part A: Area = length * width = (6x^2 + 3x - 2) * (x^3 - 2x + 5)
Multiply it out and simplify.
part B: </span><span>Take the first term 6x^2 and multiply each of the term x^3, -2x & 5. Then take 3x and multiply each of the term x^3, -2x & 5. Do the same with -2.
Then add like terms and simplify.</span>
Answer: 5 multiples of 9
Step-by-step explanation:
First take the difference between 100 and 60.
100-60=40
Then divide the difference by 9.
40/9=4.44
4.44 rounded up is 5 ==> 5 multiples of 9
Primero toma la diferencia entre 100 y 60.
100-60=40
Luego divide la diferencia entre 9.
40/9=4,44
4.44 redondeado es 5 ==> 5 múltiplos de 9
