Answer:
- 19
Step-by-step explanation:
Step 1:
3m - 10 Equation
Step 2:
3 ( - 3 ) - 10 Substitute - 3 for m
Step 3:
- 9 - 10 Multiply
Answer:
- 19 Subtract
Hope This Helps :)
Answer:
See explanation below.

Step-by-step explanation:
Notation
First we need to define the following events:
E = The student is in a major of enginnering
O= The student is in a major different from enfinnering
M= The student is in the marching band
Solution for the problem
For this case we can calculate the following probability:

And that represent the following event: "Given a randomly selected student is an engineering major, what is the probability the student is in the marching band"
And the probability that need to calculate to compare is this one:

And that represent the following event: "Given a randomly selected student is NOT an engineering major, what is the probability the student is in the marching band"
And if the claim is satisfied we need to see this:

Answer:
Step-by-step explanation:
First, add 3 to both sides:
-5 = -6∛(x²)
Next, divide both sides by -6, to isolate ∛(x²):
5/6 = ∛(x²)
Eliminate the radical by cubing both sides:
5³
---- = x²
6³
Finally, take the square root of both sides. This will isolate x. There will be two roots: one +, the other -.
x = ±√(5³/6³)
This simplifies to: ± (5/6)∛(5/6).
Answer:
<u>Sum</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>G</u><u>.</u><u>P</u><u> </u><u>is</u><u> </u><u>-</u><u>3</u><u>2</u><u>8</u><u>0</u>
Step-by-step explanation:
Summation:

<h2>
Answer:</h2>
∠LMN is a right angle
<h2>
Step-by-step explanation:</h2>
If we want to prove that two right triangles are congruent by knowing that the corresponding hypotenuses and one leg are congruent, we begin as follows:
- Since two legs are congruent and we know this by the hash marks, then the triangle ΔLKN is isosceles.
- By definition LN ≅ NK
- If ∠LMN is a right angle, then MN is the altitude of triangle ΔLKN
- Also MN is the bisector of LK, so KM ≅ ML
- So we have two right triangles ΔLMN and ΔKM having the same lengths of corresponding sides
- In conclusion, ΔLMN ≅ ΔKMN