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g100num [7]
3 years ago
6

A small dog is trained to jump straight up a distance of 1.2m. How much kinetic energy does the 7.2kg dog need to jump this high

? (The acceleration due to gravity is 9.8m/s2.) Please show work & and explain in simple terms...
Physics
2 answers:
Bas_tet [7]3 years ago
5 0
Remember that since energy is conserved, the kinetic energy it takes to jump to a height of 1.2 m is just the same as the potential energy difference between ground level and the 1.2 m height.
Potential energy = (mass)(gravity)(height) = (7.2 kg)(9.81 m/s^2)(1.2 m) = 84.76 J
Therefore, the kinetic energy required for the dog to jump to a 1.2-m height is 84.76 Joules.
lesantik [10]3 years ago
3 0
The answer is A. 85 J
This is because we rounded 84.7 to 85
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4.80 \times 10^3 \text { seconds }  long does it take to boil away 2.40 kg of the liquid.

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amount of heat required to boil

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Power $p=\frac{\text { work }}{\text { time }}=\frac{\text { Energy }}{\text { Time }}$

$$\begin{aligned}P &=\frac{Q}{t} \\\text { tine } t &=\frac{Q}{P}=\frac{4.80 \times 10^4 \mathrm{~J}}{10} \\t &=4.80 \times 10^3 \text { seconds }\end{aligned}$$

The heat or energy that is absorbed or released during a substance's phase shift is known as latent heat. It could go from a solid to a liquid or from a liquid to a gas, or vice versa. Enthalpy, a characteristic of heat, is connected to latent heat.

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For learn more about Latent heat of vaporization, visit: brainly.com/question/14980744

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3 0
1 year ago
Which two particles would be attracted to each other?
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2 years ago
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3 years ago
What is the temperature of a sample of gas when the average translational kinetic energy of a molecule in the sample is 8.37 × 1
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Answer:

404K

Explanation:

Data given, Kinetic Energy.K.E=8.37*10^-21J

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This relationship can be expressed as

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Hence if we substitute the values, we arrive at

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