Answer:
be clearer. your question doesn't seem to be presented well
Answer:
see explaination
Explanation:
function [] =
inverse(A,B)
da = det(A);
disp("The det of A is");
disp(da);
inva = inv(A);
disp("The inverse of A is");
disp(inva);
x = inva*B;
disp("The value of X is");
disp(x);
rk = rank(A);
disp("The rank of X is");
disp(rk);
Di = eig(A);
disp("The eigen values of A is");
disp(Di);
[V,Di] = eig(A);
disp("The eigen vectors of A are (Each column represents one column vector)");
disp(V);
end
A = [1,2;4,5];
B = [1,2;4,5];
inverse(A,B);
%ab = [num2str(t)," ",num2str(dx)," ",num2str(dy)];
%disp(ab);
Answer:
I'm pretty sure it's photogenic drawing.
Answer:
dominance
Explanation:
i just took it and got it right
