Its rays point away from the charge
This question is incomplete; here is the complete question:
Marco is conducting an experiment. He knows the wave that he is working with has a wavelength of 32.4 cm. If he measures the frequency as 3 hertz, which statement about the wave is accurate?
A. The wave has traveled 32.4 cm in 3 seconds.
B. The wave has traveled 32.4 cm in 9 seconds.
C. The wave has traveled 97.2 cm in 3 seconds.
D. The wave has traveled 97.2 cm in 1 second.
The answer to this question is D. The wave has traveled 97.2 cm in 1 second.
Explanation:
The frequency of a wave, which is in this case 3 hertz, represents the number of waves that go through a point during 1 second. According to this, if the frequency of the wave is 3 hertz this means in 1 second there were 3 waves. Moreover, if you multiply the wavelength (32.4cm) by the frequency (3) you will know the distance the wave traveled in 1 second: 32.4 x 3 = 97.2 cm. This makes option D the correct one as the distance in 1 second was 97.2 cm.
Answer:
He is testing for voltage drop (voltage drop test)
Explanation:
Connecting the red lead of a voltmeter to the B+ output to an ac generator and black lead to a battery +ve terminal measures the voltage drop in the circuit when the engine is turned ON and all electrical accessories too.
with this he knows if the alternator is charging the battery.
To solve this problem it is necessary to apply the concepts related to the relationship between tangential velocity and centripetal velocity, as well as the kinematic equations of angular motion. By definition we know that the direction of centripetal acceleration is perpendicular to the direction of tangential velocity, therefore:

Where,
V = the linear speed
r = Radius
Angular speed
The angular speed is given by


Replacing at our first equation we have that the centripetal acceleration would be



To transform it into multiples of the earth's gravity which is given as
the equivalent of 1g.


PART B) Now the linear speed would be subject to:



Therefore the linear speed of a point on its edge is 51.05m/s
The speed he was moving at when he finished falling is 30 m/s.
The given parameters;
mass of the bungee, m = 80 kg
impulse provided by the rope, J = 3200 Ns
initial upward velocity of the jumper, u = 10 m/s
- Let the final velocity after falling = v
- Let the upwards motion = negative
- Let the downwards motion when falling = positive
Apply the principle of conservation of linear momentum;
J = ΔP = Δmv = m(v - u)
3200 = 80(v - (-10))
3200 = 80(v + 10)

Thus, the speed he was moving at when he finished falling is 30 m/s.
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