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IgorLugansk [536]
3 years ago
13

A 10 kg computer accelerates at a rate of 5 m/s2. How much force was applied to the computer?​

Physics
2 answers:
worty [1.4K]3 years ago
8 0

Answer:

<h2>50 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 10 × 5

We have the final answer as

<h3>50 N</h3>

Hope this helps you

AURORKA [14]3 years ago
6 0

Answer:

<h2><u>Given </u><u>:</u><u>-</u><u> </u></h2>
  • Mass = 10 kg
  • Acceleration = 5 m/s²
<h2><u>To </u><u>find</u></h2>

Force applied

<h2>SoluTion</h2>

As we know that Force applied is the product of mass and acceleration

\sf \: force \:  = 5 \times 10

\sf \: force \: =  50 \: n

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Answer:

the number of photons of yellow light does the lamp generate in 1.0 s is 7 x 10^{19}

Explanation:

given information:

power, P = 25 W

wavelength. λ - 580 nm = 5.80 x 10^{-7} m

time, t = 1 s

to calculate the number of photon(N), we use the following equation

N = λPt/hc

where

λ = wavelength (m)

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t = time interval (s)

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So,

N = λPt/hc

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3 years ago
Which is a characteristic of projectile motion?A force can affect the _____ of an object.
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Answer:

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Explanation:

because mass of an object changes it’s force

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2 years ago
A 54.0 kg ice skater is gliding along the ice, heading due north at 4.10 m/s . The ice has a small coefficient of static frictio
lesya [120]

Answer:

a. 2.668 m/s

b. 0.00494

Explanation:

The computation is shown below:

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As the wind does not move the skater to the east little work is performed in this direction. All the work goes in the direction of the N-S. And located in that direction the component of the Force.

F = 3.70 cos 45 = 2.62 N

W = F \times d = 2.62 N \times 100 m

W = 261.6 N\times m

We know that

KE1 = Initial kinetic energy

KE2 = kinetic energy following 100 m

The energy following 100 meters equivalent to the initial kinetic energy less the energy lost to the work performed by the wind on the skater.

So, the equation is

KE2 = KE1 - W

0.5 m\times v2^2 = 0.5 m\ v1^2 - W

Now solve for v2

v2 = \sqrt{v1^2 - {\frac{2W}{M}}}

= \sqrt{4.1 m/s)^2 - \frac{2 \times 261.6 N\times m}{54.0 kg}}

= 2.668 m/s

b. Now the minimum value of Ug is

As we know that

Ff = force of friction

Us = coefficient of static friction

N = Normal force = weight of skater

So,

Ff = Us\times N

Now solve for Us

= \frac{Ff}{N}

= \frac{3.70 N \times cos 45 }{54.0 kg \times 9.81 m/s^2}

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3 years ago
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Assume that you can heat water with perfect insulation (all the heat from combustion of ethanol is transferred to water). What i
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Answer:

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The density of ethanol is 0.78 g/ml.

The volume of ethanol required is

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8 0
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