Answer:
4.6 years
Explanation:
This is solved using Kepler's third law which says:
Where
T = Orbital period of the planet (in seconds)
a = Distance from the star (in meters)
G = Gravitational constant
M = Mass of the parent star (in kg)
From the information given
We put this into Kepler's law and get:
This when converted to years is 4.6 years.
Answer:
Q1 = +2.50 x 10^-5C and Q2 = -2.50 x 10^-5C, r = 0.50m, F=?
Using Coulomb's law:
F = 1/(4πE) x Q1 x Q2/ r^2
Where
k= 1/(4πE) = 9 x 10^9Nm2/C2
Therefore,
F = 9x 10^9 x 2.50 x 10^-5 x2.50 x
10^-5/. ( 0.5)^2
F= 5.625/ 0.25
F= 22.5N approximately
F= 23N.
To find the direction of the force: since Q1 is positive and Q2 is negative, the force along Q1 and Q2 is force of attraction.
Hence To = 23N, attractive. C ans.
Thanks.
Answer:
height of the opening actually measure is 4'-9"
Explanation:
given data
window size = 3'-3" x 4'-9"
solution
height of the opening should actually measure will be 4'-9" in 3'-3" x 4'-9"
because according to architectural plan height can not be more than the opening size of window
and we can't take smaller height also
so fit in opening window we should take same height of height of opening window and that is here 4'-9"
so here height of the opening actually measure is 4'-9"
Answer:
Explanation:
From the given information:
Let the first weight be 
= 80 kg
The weight of the buddy be 
= 120 kg
The weight of Bubba be 
= 60 kg
Also, since you and Budda are a distance of 4m to each other, then the length to which both meet buddy will be:
The length of the boat be 
= 4 m
∴
We can find the center of mass of the system by using the formula:
She recoil at a high speed than a low
