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iris [78.8K]
2 years ago
8

A bungee jumper of mass 80kg jumps from a platform.

Physics
1 answer:
klio [65]2 years ago
5 0

The speed he was moving at when he finished falling is 30 m/s.

The given parameters;

mass of the bungee, m = 80 kg

impulse provided by the rope, J = 3200 Ns

initial upward velocity of the jumper, u = 10 m/s

  • Let the final velocity after falling = v
  • Let the upwards motion = negative
  • Let the downwards motion when falling = positive

Apply the principle of conservation of linear momentum;

J = ΔP = Δmv = m(v - u)

3200 = 80(v - (-10))

3200 = 80(v + 10)

v+ 10 = \frac{3200}{80} \\\\v+ 10 = 40\\\\v = 40-10\\\\v = 30 \ m/s

Thus, the speed he was moving at when he finished falling is 30 m/s.

Learn more here:brainly.com/question/19027317

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A remote controlled toy car starts from rest and begins to accelerate in a straight line. The figure below represents "snapshots
Nikolay [14]

(a). The car's average velocity between t = 1.0s to t = 1.5s will be - 1\;m/s

(b). The car's acceleration at t = 1.5s will be - 0.4\;m/s^{2}

(c). Car's speed is increasing with time.

We have a a remote controlled toy car that starts from rest and begins to accelerate in a straight line.

We have to determine -

  • The car's average velocity (in m/s) in the interval between -

        t = 1.0 s  to  t = 1.5 s.

  • The car's acceleration at t = 1.5 s.
  • Determining whether car's speed increasing or decreasing with time.

<h3>What is Acceleration?</h3>

The rate of change of velocity with respect to time is called Acceleration. Mathematically -

$a=\frac{dv}{dt}

According to the question, we have the following data for the Car -

t = 0s → x = 0m

t = 0.5s → x = 0.1m

t = 1.0s → x = 0.4m

t = 1.5s → x = 0.9m

t = 2.0s → x = 1.6m

PART - A

The car's average velocity between t = 1.0s to t = 1.5s will be -

$v_{avg} = \frac{0.9-0.4}{1.5-1}= 1 m/s

PART - B

Velocity at t = 1.5 s will be -

$v(1.5)=\frac{0.9}{1.5}= 0.6\;m/s

The car's acceleration at t = 1.5s will be -

$a(1.5) = \frac{v}{t} = \frac{0.6}{1.5} = 0.4\;m/s^{2}

PART - C

Since, the acceleration of the car is positive, this means that the car is accelerating in the forward direction. Hence, its speed is increasing with time.

[ The following data was missing in your answer. The complete question would include this data also -

t = 0s → x = 0m

t = 0.5s → x = 0.1m

t = 1.0s → x = 0.4m

t = 1.5s → x = 0.9m

t = 2.0s → x = 1.6m ]

To solve more questions on Kinematics, visit the link below-

brainly.com/question/17272824

#SPJ2

7 0
2 years ago
Read 2 more answers
Help me quick!!! please!!
Rudik [331]

Answer:

39.240 W

Explanation:

Let's start by calculating the work done by the engine. We can assume that it is the same work done by the weight of the object to bring it from 40m to the surface: as much energy it takes to bring it up, the same ammount it takes to bring it down. Said work is w= \vec F\cdot \vec{h} = mg h = 1000 \times 9.81\times 40 = 392.400 J

At this point we can simply apply the definition of power, that is P = \frac wt, to get the power of the engine is 39.240 W

4 0
3 years ago
Read 2 more answers
Which type(s) of electromagnetic radiation do human bodies emit? Which type(s) can our senses detect?
Andrei [34K]
Our bodies emit heat, and nerve endings in our skin can detect it.
Our eyes can detect visible light, but our bodies don't emit that.
6 0
3 years ago
A bullet with a mass of 0.02 kg is fired horizontally into a block of wood hanging on a string. The bullet sricks in the wood an
djyliett [7]

Answer:

u= 20.09 m/s

Explanation:

Given that

m = 0.02 kg

M= 2 kg

h= 0.2 m

Lets take initial speed of bullet = u m/s

The final speed of the system will be zero.

From energy conservation

1/2 m u²+ 0 = 0+ (m+M) g h

m u²=2 (m+M) g h

By putting the values

0.02 x u² = 2 (0.02+2) x 10 x 0.2       ( take g=10 m/s²)

u= 20.09 m/s

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3 years ago
What is the farthest planet from earth?
IRINA_888 [86]
The answer is pluto. just look it up
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