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Mademuasel [1]
3 years ago
14

Answer this and I’ll make you Brainly!!!!

Mathematics
1 answer:
OLga [1]3 years ago
8 0

Answer:

f(x) = 8x + 2

Step-by-step explanation:

An easy way to test what the function is, is to fill in x wiht one of the imputs, lets try two of the options, 0 and then -4

If we fill in the x as 0 we have

8(0) +2 = 2               (Put it into the equation equal to the output) Now simplify

0+2=2                    Anything times 0 is 0, now wehave

2 = 2                  This proves that the equation is correct

If we tried it with -4 we would also see it is correct

8(-4) +2 = -30                First multiply the -4 and 8 because of PEMDAS

-32 + 2 = -30                Now simplify

-30 = -30           This proves that the equation works, if you had tried one of the other equations they wouldn't have been equal if you had only used the f(x) = 8x              with the 0 it wouldn't have worked

8(0) = 2

0 ≠ 2

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Answer:

36/5

Step-by-step explanation:

x/3 + 6 -2x = -6

multiply the whole equation by 3 to get rid of the denominator of the first x term.

x+18-6x = -18

move x terms to one side and numerical terms to the other, subtract 18 from both sides in this case

x+18-6x-18=-18-18

x-6x = -36

simplify

-5x = -36

divide both sides by -5 to isolate x

x = -36/-5

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3 0
3 years ago
How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

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3 years ago
The fifth,ninth and sixteenth term of a Linear sequence are the consecutive term of an exponential sequence. Find the common dif
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Answer:

vfbg

Step-by-step explanation:

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Kim because just cause man. 14/12 can be turned into 7/6... boom knowledge??
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3 years ago
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victus00 [196]

Answer:

Domain) all x

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Step-by-step explanation:

The domain is the x values and the range is the y values

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