Answer: 83.74L
Explanation:
Temp. = 295K
P = 713torr = 0.938atm
Mass = 2.65g
PV = nRT
V = nRT/PV
n = Mass/Molar mass
Molar mass of Hydrogen gas = 1.00784*2= 2.0156g/mok
n = 2.65/2.0156 = 1.31469mol
V = 1.31469*0.08205*295/0.938
V = 83.74L
The volume = 83.74L
Answer:

Explanation:
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In this case, since these calorimetry problems are characterized by the fact that the calorimeter absorbs the heat released by the combustion of the substance, we can write:

Thus, given the temperature change and the total heat capacity, we obtain the following total heat of reaction:

Now, by dividing by the moles in 1.04 g of cyclopropane (42.09 g/mol) we obtain the enthalpy of combustion of this fuel:

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Answer:
c
Explanation:
chemicals can be found in every part of our lives