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swat32
3 years ago
15

14. Compare the graph below to the function

Mathematics
1 answer:
Dahasolnce [82]3 years ago
5 0

Answer:

Option (2)

Step-by-step explanation:

Parent function has been given as,

f(x) = \sqrt{x}

When translated by 3 units left,

f(x + 3) = \sqrt{(x+3)}

g(x) = \sqrt{(x+3)}

If the translated function is stretched vertically by a scale factor = k

New function will be,

g'(x) = k\sqrt{(x+3)}

Since a point (1, 4) passes lies on the transformed function.

g'(1) = k\sqrt{(1+3)}

4 = 2k

k = 2

Therefore, transformed function represents the translation by 3 units in the negative side of the x-axis and stretched vertically by 2 units.

Option (2) will be the answer.

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Can someone help me with this?​
Anna35 [415]

Answer:

Let 'a' be the first term, 'r' be the common ratio and 'n' be the number of terms

Series = 2+6+18.......= 2+2•3¹+ 2•3².......= 728

Now,

Sum =  \frac{a( {r}^{n} - 1) }{(r - 1)}   \\

So,

\frac{a( {r}^{n} - 1)}{(r - 1)}  = 728 \\  \frac{2( {3}^{n} - 1) }{(3 - 1)}  = 728 \\  \frac{2( {3}^{n} - 1) }{2}  = 728 \\  {3}^{n}  - 1 = 728 \\ {3}^{n}=728+1\\ {3}^{n}  = 729 \\  {3}^{n}  =  {3}^{6}  \\ \boxed{ n = 6}

Therefore, number of terms is 6

  • 6 is the right answer.
3 0
2 years ago
Pls help I will give brainlest 22, 18, 14, 10, ...
natima [27]
I just did this my bad bro
4 0
2 years ago
Pythagoras help needed please
boyakko [2]

Answer:

See explanation

Step-by-step explanation:

Find the diagonal of the square. The side of the square is 5 cm long. By the Pythagorean theorem,

\text{Diagonal}^2=\text{Side}^2+\text{Side}^2\\ \\\text{Diagonal}^2=5^2+5^2\\ \\\text{Diagonal}^2=25+25\\ \\\text{Diagonal}^2=50\\ \\\text{Diagonal}=\sqrt{50}=5\sqrt{2}\approx 7.07\ cm

If the square (being inside the circle) touches the circle, then the diagonal of the square is exactly the diameter of the circle. The diameter of the circle is twice the radius of the circle, so

\text{Diameter}=2\times 5=10\ cm

Since the diagonal is shorter than the diameter, the square can fit into the circle without touching the circle.

6 0
3 years ago
Assuming x > 0, which of these expressions is equivalent to 11 times the square root of 245 x to the third plus 9 times the s
ehidna [41]
The answer is <span>104 x times the square root of 5 x 
</span>
<span>11 times the square root of 245 x to the third plus 9 times the square root of 45 x to the third is:
</span>11 \sqrt{245 x^{3} } +9 \sqrt{45 x^{3} } =11 \sqrt{245}  *\sqrt{ x^{3} } +9 \sqrt{45} *\sqrt{ x^{3} }= \\  \\ =11 \sqrt{5*49} * \sqrt{ x^{2} *x} +9 \sqrt{5*9} * \sqrt{ x^{2} *x}= \\  \\ =11* \sqrt{5}  * \sqrt{49} * \sqrt{ x^{2}} * \sqrt{x} +9* \sqrt{5} * \sqrt{9} * \sqrt{ x^{2} }* \sqrt{x} = \\  \\ &#10;=11* \sqrt{5} *7*x* \sqrt{x} +9* \sqrt{5} *3*x* \sqrt{x} = \\  \\ &#10;=77x* \sqrt{5*x} +27x* \sqrt{5*x}  = \\  \\ &#10;=77x \sqrt{5x} +27x \sqrt{5x} = \\  \\ &#10;=104x \sqrt{5x}
4 0
2 years ago
Read 2 more answers
5x-3 and 2x+ 25, find the value of x
andreev551 [17]
If they are equal then,
5x-3=2x+25
3x=22
X=7 +1/3=7.(3)
3 0
2 years ago
Read 2 more answers
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