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swat32
3 years ago
15

14. Compare the graph below to the function

Mathematics
1 answer:
Dahasolnce [82]3 years ago
5 0

Answer:

Option (2)

Step-by-step explanation:

Parent function has been given as,

f(x) = \sqrt{x}

When translated by 3 units left,

f(x + 3) = \sqrt{(x+3)}

g(x) = \sqrt{(x+3)}

If the translated function is stretched vertically by a scale factor = k

New function will be,

g'(x) = k\sqrt{(x+3)}

Since a point (1, 4) passes lies on the transformed function.

g'(1) = k\sqrt{(1+3)}

4 = 2k

k = 2

Therefore, transformed function represents the translation by 3 units in the negative side of the x-axis and stretched vertically by 2 units.

Option (2) will be the answer.

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6 eggs

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1 year ago
SUppose the total cost C(x) to manufacture a quantity x of insecticide (in hundreds of liters) is given by
Hitman42 [59]

Answer:

a) C(x) is increasing in two regions: (i) (+\infty, 8\,s) and (ii) (10\,s,+\infty).

b) C(x) decreases in (8\,s, 10\,s).

Step-by-step explanation:

Let C(x) = x^{3}-27\cdot x^{2}+240\cdot x +850, where x is the quantity of insecticide, measured in hundreds of liters, and C(x) is the total manufacturing cost as a function of the quantity of the insecticide, measured in US dollars. A possible approach to determine which regions of C(x) are decreasing and increasing by means of the first derivative and graphing tools. The first derivative of the function is:

C'(x) = 3\cdot x^{2}-54\cdot x+240 (1)

Please notice that regions where C(x) is increasing has C'(x) > 0, whereas C'(x) < 0 when C(x) < 0.

We notice that C(x) is increasing in two regions: (i) (+\infty, 8\,s) and (ii) (10\,s,+\infty). Besides, C(x) decreases in (8\,s, 10\,s).

6 0
3 years ago
5(x+6)+11=25-3x what is the answer?
Zolol [24]
This is how I did it:
5(x + 6) + 11 = 25 - 3x          use distribution
5x + 30 + 11 = 25 - 3x          use addition
5x + 41 = 25 - 3x                  use addition and subtraction
8x = -16                                use division
x = -16/8
x = -2

So your answer is x = -2


3 0
3 years ago
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