You'll get destructive interference if both waves are the same frequency but the peaks of one wave overlap the troughs of the other wave.
That can only happen if one wave has to travel (1/2 wavelength) farther than the other one to reach your ears. So we want to find the lowest frequency for which 52 cm is 1/2 of a wavelength ... the wavelength is 104 cm.
Frequency = (speed) / (wavelength)
Frequency = (344 m/s) / (104 cm)
Frequency = (344 m/s) / (1.04 meter)
Frequency = (344 / 1.04) per second
Frequency = 330.8 Hz .
Answer:
Explanation:
Let the charge on proton be q .
energy gain by proton in a field having potential difference of V₀
= V₀ q
Due to gain of energy , its kinetic energy becomes 1/2 m v₀²
where m is mass and v₀ is velocity of proton
V₀ q = 1/2 m v₀²
In the second case , gain of energy in electrical field
= 2 V₀q , if v be the velocity gained in the second case
2 V₀q = 1/2 m v²
1/2 m v² = 2 V₀q = 2 x 1/2 m v₀²
mv² = 2 m v₀²
v = √2 v₀
Answer:
The force is 
Explanation:
We can apply the following expression
To find the area of rectangular tent wall:
Now to find the force:
Our eyes.... they send in image to our brain that's how we see... this isn't sarcasm
Answer:
By a factor of 9/4
Explanation:
Applying Coulomb's law,
F = kqq'/r²................... Equation 1
Assuming q and q' are the two point charges respectively.
Where k = coulomb's constant, r = distance between the charges.
When the point charges are 3.0 m apart,
F = kqq'/3²
F = kqq'/9.................... Equation 1
When they are moved to a new distance, 2.00 m
F' = kqq'/2²
F' = kqq'/4................. Equation 2.
Comparing equation 1 and equation 2.
F' = 9F/4
Hence the resulting mutual force change by a factor of 9/4
