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1 year ago

a 150 N force is used to pull a wooden box across a wooden surface at a constant velocity. what is the mass of the box?

Physics

1 answer:

IRINA_888 [86]1 year ago

7 0

Answer:

The mass of the box:

m = 60 kg

Explanation:

Given:

F = 150 N

g = 10 m/s²

_________

m - ?

Coefficient of friction wood on wood:

μ = 0.25

Friction force:

F₁ = μ*m*g

Newton's Third Law:

F = F₁

F = μ*m*g

The mass of the box:

m = F / ( μ*g) = 150 / (0.25*10) = 60 kg

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An ideal pendulum is often discussed when studying simple harmonic motion. What are the conditions needed for an ideal pendulum?

vlada-n [284]

Complete question is;

An ideal pendulum is often discussed when studying simple harmonic motion.

What are the conditions needed for an ideal pendulum? Check all that apply.

1) Gravitational force acts to pull the pendulum’s mass down.

2) The mass of the rod of the pendulum is evenly distributed along the rod.

3) The pivot on which the pendulum swings is frictionless.

4) The pendulum swings through its equilibrium position as a result of inertia.

5) Tension acts downward on the pendulum’s mass

Answer:

Conditions 2,3 & 4 are the ones that apply

Explanation:

The conditions required for an ideal pendulum are;

- The mass of the rod of the pendulum has to be evenly distributed along the rod.

- Ensure that the pivot on which the pendulum is swinging is frictionless

-The pendulum has to swing through it's equilibrium position as a result of inertia.

Thus,the correct options are 2, 3, 4.

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2 years ago

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What is another word that can be used to describe the position of the object?

steposvetlana [31]

where the object is located

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2 years ago

An object is moving forward with a constant velocity. Which statement about this object MUST be true?

Greeley [361]

If the object's velocity is constant ... (it's speed isn't changing AND it's moving in a straight line) ... then the net force on the object is zero. (D)

Either there are no forces at all acting on the object, OR there are forces on it but they're 'balanced' ... when you add up all of their sizes and directions, they just exactly cancel each other out, and they have the SAME EFFECT on the object as if there were no forces at all.

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3 years ago

In Example 2.12, two circus performers rehearse a trick in which a ball and a dart collide. Horatio stands on a platform 6.4 m a

pickupchik [31]

Answer:

time of collision is

t = 0.395 s

$h = 5.63 m$

so they will collide at height of 5.63 m from ground

Explanation:

initial speed of the ball when it is dropped down is

$v_1 = 0$

similarly initial speed of the object which is projected by spring is given as

$v_2 = 16.2 m/s$

now relative velocity of object with respect to ball

$v_r = 16.2 m/s$

now since we know that both are moving under gravity so their relative acceleration is ZERO and the relative distance between them is 6.4 m

$d = v_r t$

$6.4 = 16.2 t$

$t = 0.395 m$

Now the height attained by the object in the same time is given as

$h = v_2 t - \frac{1}{2}gt^2$

$h = 16.2(0.395) - \frac{1}{2}(9.81).395^2$

$h = 5.63 m$

so they will collide at height of 5.63 m from ground

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3 years ago

The vector product of vectors A⃗ and B⃗ has magnitude 12.0 m2 and is in the +z-direction.Vector A⃗ has magnitude 4.0 m and is in

g100num [7]

Answer:

θ=180°

Explanation:

The problem says that the vector product of A and B is in the +z-direction, and that the vector A is in the -x-direction. Since vector B has no x-component, and is perpendicular to the z-axis (as A and B are both perpendicular to their vector product), vector B has to be in the y-axis.

Using the right hand rule for vector product, we can test the two possible cases:

If vector B is in the +y-axis, the product AxB should be in the -z-axis. Since it is in the +z-axis, this is not correct.

If vector B is in the -y-axis, the product AxB should be in the +z-axis. This is the correct option.

Now, the problem says that the angle θ is measured from the +y-direction to the +z-direction. This means that the -y-direction has an angle of 180° (half turn).

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2 years ago