Well to find speed you have to do distance /time. So, in this case you do 112m /29s which it will be 3.862 which if you round it, it will be 3.86 m/s
The value given is called the Avogadro's number. It is the number of particles in every 1 mole of any substance. I think this is a trial and error process. Input 6.022x10^23 into your calculator. Add to this a number consisting of the maximum digit which is 9. Apparently, when 10×10¹³ is added, the display already changes. Therefore, the largest number would have to be 10×10¹².
Answer:
(4)KBr(aq)
Explanation:
A mixture is an impure substance made up of two or more substances that are joined together. Their composition is indefinite and not easily represented by a simple chemical formula.
KBr
is a mixture because it made up of an aqueous solution of KBr. This suggests that the substance KBr is placed inside water.
Here, we have two states of matter which is the solid and the liquid coming together.
As with both mixtures, they can be separated by physical means, KBr aqueous solution can also be done this way.
The equilibrium reaction that is not shown is the reaction of N₂ and O₂ to form NO:
N₂ + O₂ ⇄ 2NO
We can write an expression for the equilibrium constant. We are given the value of Kc, but we must use Kp if we are dealing with partial pressures. However, since 2 moles of gas are formed from 2 moles of gas, the value of Kc is equal to Kp so we do not need to change anything.
Kc = (Pno)²/(Pn2)(Po2) = 1.71 x 10⁻¹
We must first use the initial pressures to find the reaction quotient to decide which way the equilibrium will shift:
Q = (1.96 x 10⁻³)²/(1.96 x 10⁻³)(1.96 x 10⁻³) = 1
Since Q > Kp, the equilibrium will shift to the left. Now we can prepare an ICE table to find the equilibrium pressures:
N₂ O₂ NO
I 1.96 x 10⁻³ 1.96 x 10⁻³ 1.96 x 10⁻³
C +x +x -2x
E 0.00196 + x 0.00196 + x 0.00196 - 2x
We enter these equilibrium pressures into the equilibrium expression and solve for x:
0.171 = (0.00196 - 2x)²/(0.00196 + x)²
Expand the equation and simplify to a quadratic function:
3.829x² - 0.00851x + 3.183·10⁻⁶ = 0
x = ((0.00851) +/- sqrt((0.00851)² - 4(3.829)(3.183 x 10⁻⁶)))/2(3.829)
x = 0.000476 atm
Now we can solve for the equilibrium partial pressures:
Pno = 0.00196 - 2(0.000476) = 0.00101 atm
Pn2 = 0.00196 + 0.000476 = 0.00244 atm
Po2 = 0.000196 + 0.000476 = 0.00244 atm
Therefore, the equilibrium partial pressure of NO is 0.00101 atm.
