A thin cylindrical shell and a solid cylinder have the same mass and radius. The two are released side by side and roll down, wi
1 answer:
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m = mass = 5 kg
= initial velocity = 100 m/s
= final velocity = ?
I = impulse = 30 Ns
Using the impulse-change in momentum equation
I = m( -
)
30 = 5 ( - 100)
= 106 m/s
Answer:
Capacitance of cylindrical capacitor does not depends on the amount of charge on the conductors
Explanation:
Consider a cylindrical capacitor of length L, inner radius R₁ and outer radius R₂, permitivity ε₀ constant then capacitance of cylindrical capacitor is given by:
From this equation it is clear that capacitance of cylindrical capacitor is independent of the amount of charge on the conductors where as directly proportional permitivity constant and length of cylinder where as inversely proportional to natural log of ratio of R₂ and R₁
Answer:
1) A
2) C
3) B
4) A
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8) A
9) C
10) C
Explanation:
1) m = 15kg, a = , F = ma = 15*10 = 150N
2) m = 3kg, v = , r = 4m, F =
= 12N
3) a = , r = 10m, v=?
F = and F = ma
equating the two equations and cancelling a, we have:
= a
making v the subject of formula, we have:
v =
=
= 10
4) r = 10m, v = , a = ?
F =
F = ma
equating the above equations and making a subject of formula, we get:
a =
a = 25/10 = 2.5
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8) F =
assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:
F =
Now, if v is tripled
F =
F = 9
We can see that the force will be 9X greater than it was.
9) F =
assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:
F =
Now, if v is doubled
F =
F = 4
We can see that the force will be 4X greater than it was.
10) F =
assuming m and v is unity, that is the values are 1 respectively
F = 1/r
if r is doubled,
F = 1/2 * 1/r
We can see that the force is 1/2 as big as it was