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lyudmila [28]
3 years ago
9

Which type of wave does the illustration depict?

Physics
2 answers:
Aleks [24]3 years ago
8 0

Answer:longitudinal wave

Explanation:

Mama L [17]3 years ago
6 0

Answer:

A.) Longitudinal wave

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Pravat exerts a force of 30 n to lift a bag of groceries 0.5 m. how much work did pravat do on the bag? note : work = force x di
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Answer in photo below

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A circus tightrope walker weighing 800 N is standing in the middle of a 15 meter long cable stretched between two posts. The cab
Lorico [155]

Answer:

T = 10010 N

Explanation:

To solve this problem we must use the translational equilibrium relation, let's set a reference frame

X axis

       Fₓ-Fₓ = 0

       Fₓ = Fₓ

whereby the horizontal components of the tension in the cable cancel

Y Axis  

        F_{y} + F_{y} - W =0

        2F_{y} = W

let's use trigonometry to find the angles

        tan θ = y / x

        θ = tan⁻¹ (0.30 / 0.50 L)

        θ = tan⁻¹ (0.30 / 0.50 15)

        θ = 2.29º

the components of stress are

         F_{y} = T sin θ

we substitute

       2 T sin θ = W

       T = W / 2sin θ

        T = \frac{ 800}{ 2sin 2.29}

        T = 10010 N

4 0
3 years ago
0.160-kg hockey puck is moving on an icy, frictionless, horizontal surface. At t 0, the puck is moving to the right at 3.00 m/s.
balandron [24]

Answer: (a)10.812\ m/s\ (b)\ 0.75\ m/s\ \text{left}

Explanation:

Given

Mass of hockey puck m=0.160\ kg

Initial velocity of hockey puck is u=3\ m/s

First a horizontal force of 25\ N is applied to the right for 0.05\ s

acceleration associated with it is

\Rightarrow a=\dfrac{25}{0.160}\\\\\Rightarrow a=156.5\ m/s^2

Using equation of motion i.e.

\Rightarrow v=u+at\\\Rightarrow v=3+156.25\times 0.05\\\Rightarrow v=3+7.812\\\Rightarrow v=10.812\ m/s

(b) When a force of 12\ N is applied for 0.05s

Using equation of motion i.e.

\Rightarrow v=3-\dfrac{12}{0.160}\times 0.05\\\\\Rightarrow v=3-75\times 0.05\\\Rightarrow v=3-3.75\\\Rightarrow v=-0.75\ m/s\\\Rightarrow v=0.75\ \text{towards left}

6 0
3 years ago
Water droplets forming on the outside of a cold glass of water on a hot, summer day is a example of which part of the water cycl
sergiy2304 [10]

Answer:

Condensation can also produce water droplets on the outside of soda cans or glasses of cold water. When warm air hits the cold surface, it reaches its dew point and condenses. This leaves droplets of water on the glass or can.

Explanation:

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A person pushes on the handle of a lawnmower with a force of 280. n. if the handle makes an angle of 40.0 degrees with the groun
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<span>Force F = 280 N Angle with the ground = 40 degrees Weight of the Lawnmower = 350 N Velocity is constant so Acceleration is 0 So Forward force Ff = F cos theta = 280 cos40 Frictional force with resists to back Fb = (u x Force from pressure) + vertical component of Force, where u is the coefficient of friction. Fb = (u x m x g) + (u x 280sin40) AS Ff = Fb => 280 cos40 = u x ((m x g) + 280sin40) u = 280 cos40 / ((350 x 9.81) + 280sin40) = 214.49 / () = 0.405 So the coefficient of friction u = 0.405</span>
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3 years ago
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