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Alika [10]
3 years ago
12

On an acceleration-time graph what are the units for acceleration

Physics
1 answer:
marysya [2.9K]3 years ago
7 0

Answer:

Possibly m/s^2 (metres per second squared)

Explanation:

There are a few different units for acceleration so I need more information, but generally the standard unit is metres per second squared.

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Ajdaifsgodtistizhxtsgoachoach
Norma-Jean [14]

Hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm maybe

8 0
2 years ago
"In regards to the global energy budget, Earth absorbs ____________ wave radiation and emits ___________ wave radiation"
OLga [1]

Answer:

In regards to the global energy budget, Earth absorbs <u>short-</u><u>wave</u> radiation and emits <u>long-</u><u>wave</u> radiation.

Explanation:

It is required to tell what kind of wave radiation the earth absorbs and emits in regards to the global energy budget.

Let us discuss the global energy budget first.

The balance between the solar energy that enters Earth and the energy that leaves Earth and travels back into space is known as the global energy budget or the earth's energy budget. The visible region of the electromagnetic spectrum is where the majority of the sun's energy is found.

Therefore earth absorbs <u>short-</u><u>wave</u> radiation and emits <u>long-</u><u>wave </u>radiation in regard to the global energy budget.

To know more about, the global energy budget, refer to:

brainly.com/question/4352906

#SPJ4

6 0
1 year ago
Where does the suns rays strike earth most direcly and least directly
julia-pushkina [17]
Most directly on equador and least directly at poluses
5 0
3 years ago
Comets travel around the sun in elliptical orbits with large eccentricities. If a comet has speed 1.6×104 m/s when at a distance
xz_007 [3.2K]

Answer:

v₂ = 7.6 x 10⁴ m/s

Explanation:

given,

speed of comet(v₁) = 1.6 x 10⁴ m/s

distance (d₁)= 2.7 x 10¹¹ m

to find the speed when he is at distance of(d₂) 4.8 × 10¹⁰ m

v₂ = ?

speed of planet can be determine using conservation of energy

K.E₁ + P.E₁ = K.E₂ + P.E₂

\dfrac{1}{2}mv_1^2-\dfrac{GMm}{r_1} = \dfrac{1}{2}mv_2^2-\dfrac{GMm}{r_2}

\dfrac{1}{2}v_1^2-\dfrac{GM}{r_1} = \dfrac{1}{2}v_2^2-\dfrac{GM}{r_2}

v_2^2= v_1^2 + \dfrac{2GM}{r_2}-\dfrac{2GM}{r_1}

v_2= \sqrt{v_1^2 +2GM(\dfrac{1}{r_2}-\dfrac{1}{r_1})}

v_2= \sqrt{(1.6\times 10^4)^2 +2\times 6.67 \times 10^{-11}\times 1.99 \times 10^{30}(\dfrac{1}{4.8\times 10^{10}}-\dfrac{1}{2.7\times 10^{11}})}

v₂ = 7.6 x 10⁴ m/s

3 0
2 years ago
Estimate the number of times the earth will rotate on its axis during a human’s lifetime
Fudgin [204]

Here we have to calculate  the number of rotations made by earth around its own axis in the entire life time of a human being.

The average human life is 50 years .

Each year is 365.5 days

Hence 50 years =50 *365.5 days

                 =18,275 days

The earth rotates around its own axis in 23 hours 56 minutes and 4 second which is approximately equal to 24 hours or one days.

Hence one rotation takes one days.

⇒18,275 days =18,275 rotations

Hence the total number of rotations made by earth around its own axis in the life time of a average human life time will be 18,275 times

7 0
3 years ago
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