Length = meters
mass = kg
weight = kg
volume = m^3 (cubic meters)
density = kg/m^3 (kilograms per cubic meter)
temperature = degrees C
time = seconds
Answer:
(a) The x-component of velocity is 31.55 km/h
(b) The y-component of velocity is 44.92 km/hr
Solution:
As per the solution:
The relative position of ship A relative to ship B is 4.2 km north and 2.7 km east.
Velocity of ship A, 
= 22 km/h towards South = 
Velocity of ship B, 
= 39 km/h Towards North east at an angle of 
= 
Now, the velocity of ship A relative to ship B:
Now,
In both scenarios, the position - time graph will be a linear graph, since the speed is constant, so your position is moving at a consistent pace.
The equation is garbled and the question is missing.
I found this equation for the same statement:
S = - 2.7t ^2 + 30t + 6.5
And one question is: after how many seconds is the ball 12 feet above the moon's surface?
Given that S is the height of the ball, you just have to replace S with 12 and solve for t.
=> 12 = - 2.7 t^2 + 30t + 6.5
=> 2.7t^2 - 30t - 6.5 + 12 = 0
=> 2.7t^2 - 30t + 5.5 = 0
Now you can use the quadratic equation fo find t:
t = { 30 +/- √ [30^2) - 4(2.7)(5.5)] } / (2*2.7)
=> t = 0.186s and t = 10.925 s
Answer: after 0.186 s the ball is at 12 feet over the surface, and again 10.925 s
