Four boys push on the front back and sides of a shopping cart. the boys in the front on the two sides push with a force of 60N.
the boy in back pushes with a force of 50N. which way does the cart move
*ASAP
*ASAP
1 answer:
Answer:
The cart will move backwards
Explanation:
To solve this problem we must make a free body diagram of the shopping cart and the forces acting on them. You have two boys pushing on the sides with a force of 60 [N] and the child on the front also pushes with a force of 60[N], the child behind pushes with a force of 50 [N].
In the attached image we can see the free body diagram.
As shown in the attached image the shopping cart is displayed from above, the forces of children pushing on the sides, are canceled with each other as they are equal in magnitude and opposite in direction. While the force of the child pushing with 60 [N] is greater than the force of the child pushing with 50 [N] therefore the cart will move backwards, that is to the left as seen in the attached scheme.
You might be interested in
To place the poles of a 1. 5 v battery to achieve the same electric field is 1.5×10−2 m
The potential difference is related to the electric field by:
∆V=Ed
where,
∆V is the potential difference
E is the electric field
d is the distance
what is potential difference?
The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other.
We want to know the distance the detectors have to be placed in order to achieve an electric field of
E=1v/cm=100v/cm
when connected to a battery with potential difference
∆v=1.5v
Solving the equation,we find
learn more about potential difference from here: brainly.com/question/28166044
#SPJ4