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givi [52]
2 years ago
13

Four boys push on the front back and sides of a shopping cart. the boys in the front on the two sides push with a force of 60N.

the boy in back pushes with a force of 50N. which way does the cart move
*ASAP

Physics
1 answer:
Art [367]2 years ago
3 0

Answer:

The cart will move backwards

Explanation:

To solve this problem we must make a free body diagram of the shopping cart and the forces acting on them. You have two boys pushing on the sides with a force of 60 [N] and the child on the front also pushes with a force of 60[N], the child behind pushes with a force of 50 [N].

 In the attached image we can see the free body diagram.

As shown in the attached image the shopping cart is displayed from above, the forces of children pushing on the sides, are canceled with each other as they are equal in magnitude and opposite in direction. While the force of the child pushing with 60 [N] is greater than the force of the child pushing with 50 [N] therefore the cart will move backwards, that is to the left as seen in the attached scheme.

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Answer:

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Explanation:

Given that,

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We need to find the magnitude of the centripetal acceleration. The formula for the centripetal acceleration is given by :

a=\dfrac{v^2}{r}\\\\a=\dfrac{(2)^2}{1}\\\\=4\ m/s^2

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2 years ago
When you stretch a spring 20 cm past its natural length, it exerts a force of 8
Nastasia [14]

Answer:

40 N/m

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Finally:

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6 0
3 years ago
Read 2 more answers
A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 500 V. The rate
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3 0
3 years ago
At the 1 s mark, which objects have equal momentum?
Rudik [331]
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3 0
2 years ago
A rifle bullet with mass ma = 8.00 g strikes and embeds itself in a block with mass mb = 0.992 kg that rests on a frictionless,
Doss [256]

Answer:

the magnitude of the velocity of the block just after impact is 2.598 m/s and the original speed of the bullect is 324.76m/s.

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Here m stands for combined mass (block + bullet),

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From the energy equation above, solve for v,

v = v √(k/m)  

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b)  Momentum before impact = momentum after impact.

Since m = 1 kg,

v = 2.598 m/s,

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6 0
3 years ago
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