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sdas [7]
3 years ago
13

At a particular instant, a moving body has a kinetic energy of 295 J and a momentum of magnitude 25.1 kg · m/s.(a)What is the sp

eed (in m/s) of the body at this instant?m/s(b)What is the mass (in kg) of the body at this instant?kg
Physics
1 answer:
motikmotik3 years ago
5 0

Answer:

a) 23.51 m/s

b) 1.07 kg

Explanation:

Parameters given:

Kinetic energy, K = 295 J

Momentum, p = 25.1 kgm/s

a) The kinetic energy of a body is given as:

K = \frac{1}{2} mv^2

where m = mass of the body and v = speed of the body

We know that momentum is given as:

p = mv

Therefore:

K = 1/2 * pv

=> v = 2K / p

v = (2 * 295) / 25.1 = 23.51 m/s

The velocity of the body at that instant is 23.51 m/s.

b) Momentum is given as:

p = mv

=> m = p / v

m = 25.1 / 23.51  = 1.07 kg

The mass of the body at that instant is 1.07 kg

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A vehicle starts from rest and accelerates uniformly for 12 seconds to a
xz_007 [3.2K]

The value of the acceleration is 0.76 m/s² and the total time taken by the vehicle is 39 seconds.

<h3>Acceleration of the vehicle</h3>

The acceleration of the vehicle before coming to rest is calculated as follows;

v² = u² + 2as

where;

  • v is the final velocity
  • u is the initial velocity
  • a is the acceleration
  • s is the distance traveled before stopping

the car came to rest with constant velocity attained after 12 seconds.

the initial velocity of the car before 12 seconds is zero.

v² = 0 + 2as

a = v²/2s

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a = 0.76 m/s²

<h3>Time of motion of the vehicle</h3>

d = ut + ¹/₂at²

where;

  • d is the total distance traveled
  • t is the time of motion
  • a is acceleration
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580 = 0 + ¹/₂(0.76)t²

580 = 0.38t²

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t = √1,526.3

t = 39 seconds

Thus, the value of the acceleration is 0.76 m/s² and the total time taken by the vehicle is 39 seconds.

Learn more about time of motion here: brainly.com/question/2364404

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