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3 years ago

A photon with a wavelength of 2.29 × 10^–7 meter strikes a mercury atom in the ground state.

1 answer:

8 0

The photon can be absorbed and the energy of the photon is exactly equal to the energy-level difference between the ground state and the level d.

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How can a driver best prepare to enter sharp curves on a road way

yawa3891 [41]

Slow down significantly before the curve in the road

5 0

3 years ago

A 40kg skier starts at the top of a 12 meter high slope at the bottom she is traveling g 10m/a how much energy does she lose to

nikdorinn [45]

Energy at top = U = mgh = 40 * 9.8 * 12 = 4704 J

Energy at bottom = 1/2 mv² = 1/2 * 40 * 10² = 4000 / 2 = 2000 J

Energy Lost = Final - Initial = 4704 - 2000 = 2704 J

In short, Your Answer would be 2704 Joules

Hope this helps!

3 0

4 years ago

Heavy water usually refers to water that : (A) has been frozen, and so is more dense (B) has had its hydrogen removed (C) is rad

Roman55 [17]

Answer:

Option (D)

Explanation:

The chemical formula for normal water is H2O and the chemical formula for heavy water is D2O.

Where D is deuterium which is the isotope of hydrogen.

There are three isotopes of hydrogen.

1H1 it is called protium.

1H2 it is called deuterium.

1H3 it is called tritium.

6 0

3 years ago

Read 2 more answers

Two identical particles, each with a mass of 4.5 mg and a charge of 30 nC, are moving directly toward each other with equal spee

e-lub [12.9K]

Answer:

r₁ = 20.5 cm

Explanation:

In this exercise we can use the conservation of energy

the gravitational power energy is always attractive, the electrical power energy is repulsive if the charges are of the same sign

starting point.

Em₀ = U_g + U_e + K = $-G \frac{m_1m_2}{r} +k \frac{q_1q_2}{r} - 2 ( \frac{1}{2} m v^2)$

the two in the kinetic energy is because they are two particles

final point. When it is detained

Em_f = U_g + U_e = $-G \frac{m_1m_2}{r_1} + k \frac{q_1q_2}{r_1}$

the energy is conserved

Em₀ = em_f

the charges and masses of the two particles are equal

$-G \frac{m^2}{r} + k \frac{q^2}{r} + m v^2 = - G \frac{m^2}{r_1} + k \frac{q^2}{r_1}$

sustitute the values

-6.67-11 (4.5 10-3) ² / 0.25 - 9, 109 (30 10-9) ² / 0.25 + 4.5 10-3 4² = - 6.67 10- 11 (4.5 10-3) ² / r1 -9 109 (30 10-9) ² / r1

-5.4 10⁻¹⁵ + 3.24 10⁻⁵ - 7.2 10⁻⁵ = -1.35 10⁻¹⁵ / r₁ + 8.1 10⁻⁶ / r₁

We can see that the terms that correspond to the gravitational potential energy are much smaller than the terms of the electric power, which is why we depress them.

3.24 10⁻⁵ - 7.2 10⁻⁵ = 8.1 10⁻⁶ / r₁

-3.96 10⁻⁵ = 8.1 10⁻⁶ / r₁

r₁ = 8.1 10⁻⁶ /3.96 10⁻⁵

r₁ = 2.045 10⁻¹ m

r₁ = 20.5 cm

4 0

3 years ago

An electromagnetic wave of wavelength 435 nm is traveling in vacuum in the —z direction. The electric field has an amplitude of

joja [24]

Answer:

a) 6.9*10^14 Hz

b) 9*10^-12 T

Explanation:

Given that

The wavelength of the wave, λ = 435 nm

Amplitude of the electric field, E(max) = 2.7*10^-3 V/m

The frequency of the wave can be found by using the formula

c = fλ, where c = speed of light

f = c/λ

f = 3*10^8 / 435*10^-9

f = 6.90*10^14 Hz

E(max) = B(max) * c, magnetic field amplitude, B(max) =

B(max) = E(max)/c

B(max) = 2.7*10^-3 / 3*10^8

B(max) = 9*10^-12 T

1T = 1 (V.s/m^2)

8 0

3 years ago