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Volgvan
3 years ago
10

A carmaker has designed a car that can reach a maximum acceleration of 12 meters per second the cars mass is 1515 assuming the s

ame engine is used what should the cars mass be if the carmaker wants it to reach an acceleration of 15meters/second

Physics
2 answers:
frosja888 [35]3 years ago
7 0

Answer:1212

Explanation:

Rudiy273 years ago
5 0
The answer is attached. Also, you should know that the unit for acceleration is m/s2 and for velocity it is m/s.

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A soccer ball of diameter 22.6cm and mass 426g rolls up a hill without slipping, reaching a maximum height of 5m above the base
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Answer with Explanation:

We are given that

Diameter=d=22.6 cm

Mass,m=426 g=426\times 10^{-3} kg

1 kg=1000 g

Radius,r=\frac{d}{2}=\frac{22.6}{2}=11.3 cm=11.3\times 10^{-2} m

1m=100 cm

Height,h=5m

I=\frac{2}{2}mr^2

a.By law of conservation of energy

\frac{1}{2}I\omega^2+\frac{1}{2}mv^2=mgh

\frac{1}{2}\times \frac{2}{3}mr^2\omega^2+\frac{1}{2}mr^2\omega^2=mgh

v=\omega r

gh=\frac{1}{3}r^2+\frac{1}{2}r^2=\frac{5}{6}r^2\omega^2

\omega^2=\frac{6}{5r^2}gh

\omega=\sqrt{\frac{6gh}{5r^2}}=\sqrt{\frac{6\times 9.8\times 5}{5(11.3\times 10^{-2})^2}}=67.86 rad/s

Where g=9.8m/s^2

b.Rotational kinetic energy=\frac{1}{2}I\omega^2=\frac{1}{2}\times \frac{2}{3}mr^2\omega^2=\frac{1}{2}\times \frac{2}{3}(426\times 10^{-3})(11.3\times 10^{-2})^2(67.86)^2=8.35 J

Rotational kinetic energy=8.35 J

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3 years ago
What's the symbol for an ionized gallium atom?
babunello [35]
Hi there!

Gallium is chemical element 31, (meaning 31 protons, 31 electrons).

The symbol for Gallium is "Ga"

Hope this helps you!

~DoctorLex
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Answer:

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Explanation:

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