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3 years ago

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Numerical: A capacitor of 200 picofarad is charged to a potential difference of 100 volts. It's plates are then connected parall

el to another capacitor them potential difference in this combination fall to 60 volts. What is the capacitance of second capacitor?
(Working of this solution)

1 answer:

alexandr1967 [171]3 years ago

7 0

Answer:

The capacitance of the other capacitor is 1333.3 pF.

Explanation:

C' = 200 pF, V' = 100 V, C'' , V''= 0

Common potential, V = 60 V

Use the formula of the common potential

$V = \frac{C' V' + C'' + V''}{C'+ C''}\\\\60 = \frac{200\times 100 + 0}{200 + C''}\\\\1200+ 6 C''= 2000\\\\C'' = 1333.3 pF$

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Answer:

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Explanation:

From the question we are told that

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Answer:

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Explanation:

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$\dfrac{h_{1}L_{1}}{k_{1}}=\dfrac{h_{2}L_{2}}{k_{2}}$

Here, $k_{1}=k_{2}$

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