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kkurt [141]
3 years ago
13

An electron in a mercury atom changes from energy level b to a higher energy level when the

Physics
1 answer:
emmainna [20.7K]3 years ago
4 0
The energy is 3.06 electronvolts,  E = 3.06eV

1eV = 1.6 * 10^-19 J

3.06 eV = 3.06* 1.6 * 10^-19 J = 4.896 * 10^-19 J


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a particle is moving with shm of period 8.0s and amplitude 5.0cm. find (a) the speed of particle when it is 3.0m from the centre
Fudgin [204]

Answer:

a) speed=\pi cm/s

b) v_{max}=\frac{5\pi}{4} cm/s

c) a_{max}=\frac{5\pi^{2}}{16} cm/s^{2}

Explanation:

The very first thing we must do in order to solve this problem is to find an equation for the simple harmonic motion of the given particle. Simple harmonic motion can be modeled with the following formula:

y=Asin(\omega t)

where:

A=amplitude

\omega= angular frequency

t=time

we know the amplitude is:

A=5.0cm

and the angular frequency can be found by using the following formula:

\omega=\frac{2\pi}{T}

so our angular frequency is:

\omega=\frac{2\pi}{8s}

\omega=\frac{\pi}{4}

so now we can build our equation:

y=5sin(\frac{\pi}{4} t)

we need to find the speed of the particle when it is 3m from the centre of its motion, so we need to find the time t when this will happen. We can use the equation we just found to get this value:

y=5sin(\frac{\pi}{4} t)

3=5sin(\frac{\pi}{4} t)

so we solve for t:

sin(\frac{\pi}{4} t)=\frac{3}{5}

\frac{\pi}{4} t=sin^{-1}(\frac{3}{5})

t=\frac{4}{\pi}sin^{-1}(\frac{3}{5})

you can directly use this expression as the time or its decimal representation:

t=0.81933

since we need to find the speed of the particle at that time, we will need to get the derivative of the equation that represents the particle's position, so we get:

y=5sin(\frac{\pi}{4} t)

y'=5cos(\frac{\pi}{4} t)*\frac{\pi}{4}

which simplifies to:

y' =\frac{5\pi}{4}cos(\frac{\pi}{4} t)

and we can now substitute the t-value we found previously, so we get:

y'=\frac{5\pi}{4}cos(\frac{\pi}{4} (0.81933))

y'=\pi

so its velocity at that point is \pi cm/s

b) In order to find the maximum velocity we just need to take a look at the velocity equation we just found:

y' =\frac{5\pi}{4}cos(\frac{\pi}{4} t)

its amplitude will always give us the maximum velocity of the particle, so in this case the amplitude is:

A=\frac{5\pi}{4}

so:

v_{max}=\frac{5\pi}{4} cm/s

c) we can use a similar procedure to find the maximum acceleration of the particle, we just need to find the derivative of the velocity equation and determine its amplitude. So we get:

y'= \frac{5\pi}{4}cos(\frac{\pi}{4} t)

We can use the chain rule again to find this derivative so we get:

y" =-\frac{5\pi}{4}sin(\frac{\pi}{4} t)*(\frac{pi}{4})

so when simplified we get:

y"=-\frac{5\pi^{2}}{16}sin(\frac{\pi}{4} t)

its amplitude is:

A=\frac{5\pi^{2}}{16}

so its maximum acceleration is:

a_{max}=\frac{5\pi^{2}}{16} cm/s^{2}

7 0
3 years ago
How long does it take to get from a new moon to a first quarter moon
Andru [333]

'First Quarter' is the phase that appears one quarter of the
period of time from one new moon to the next one.

The total period of the moon's phases is 29.53 days (rounded).

One quarter of it is (29.53 / 4) =  <em>7 days  9.2 hours</em>   (rounded)


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4 years ago
Chang sees the following formula on a website about Newton’s second law. a = Sigma F over m.
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Answer:A) he needs to find the net force acting on an object in a direction.

Explanation:

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Neo and the agent stand in different locations and the length of the line between them (their distance apart) is a measurement o
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In two-dimensional space, both directions located in the same plane , and the distance in locations only separated by width and length (there is no volume in this model)
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B Minerals must be solid, have an orderly atomic structure, have a recognized chemical composition, be naturally occurring, and
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Minerals must be solid, have an orderly atomic structure, have a recognized chemical composition, be naturally occurring and <u>inorganic in origin</u>.

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