Fluids flow and exert forces on objects.

3. Riddle:

beks73 [17]

Answer:

The answer is charcoal

3 0

3 years ago

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The voyage of the H.M.S what important because

yaroslaw [1]

C. Physicalist chemist and biologist conducted experience in gather collection that changed existing scientific knowledge about the oceans

Explanation:

The voyage of Her Majesty's Ship was highly important because it furnished scientists with rich evidence about a lot of phenomenon under study and this changed existing scientific knowledge about the ocean.

H.M.S II was an expedition to study and map the ocean floor using some sophisticated and newer devices.
It was through this expedition that the theory of plate tectonics was modified and became a theory
The bathymetry of the ocean floor was also carried out.
The mid-oceanic ridge was discovered through the expedition.
Some rare species of organisms were also obtained from the ocean floor in this process.
The H.M.S second expedition after the world war was very crucial and helped furthered scientific knowledge about the oceans.

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Sea floor spreading brainly.com/question/9912731

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7 0

3 years ago

Which value is equivalent to 178 centimeters?

seraphim [82]

Answer:

jsuddjjddj

Explanation:

nzjdnzjdndk

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3 years ago

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A counterflow double-pipe heat exchanger is used to heat water from 20°C to 80°C at a rate of 1.2 kg/s. The heating is to be com

bixtya [17]

Answer:L=109.16 m

Explanation:

Given

initial temperature $=20^{\circ}C$

Final Temperature $=80^{\circ}C$

mass flow rate of cold fluid $\dot{m_c}=1.2 kg/s$

Initial Geothermal water temperature $T_h_i=160^{\circ}C$

Let final Temperature be T

mass flow rate of geothermal water $\dot{m_h}=2 kg/s$

diameter of inner wall $d_i=1.5 cm$

$U_{overall}=640 W/m^2K$

specific heat of water $c=4.18 kJ/kg-K$

balancing energy

Heat lost by hot fluid=heat gained by cold Fluid

$\dot{m_c}c(T_h_i-T_h_e)= \dot{m_h}c(80-20)$

$2\times (160-T)=1.2\times (80-20)$

$160-T=36$

$T=124^{\circ}C$

As heat exchanger is counter flow therefore

$\Delta T_1=160-80=80^{\circ}C$

$\Delta T_2=124-20=104^{\circ}C$

$LMTD=\frac{\Delta T_1-\Delta T_2}{\ln (\frac{\Delta T_1}{\Delta T_2})}$

$LMTD=\frac{80-104}{\ln \frac{80}{104}}$

$LMTD=91.49^{\circ}C$

heat lost or gain by Fluid is equal to heat transfer in the heat exchanger

$\dot{m_c}c(80-20)=U\cdot A\cdot$ (LMTD)

$A=\frac{1.2\times 4.184\times 1000\times 60}{640\times 91.49}=5.144 m^2$

$A=\pi DL=5.144$

$L=\frac{5.144}{\pi \times 0.015}$

$L=109.16 m$

6 0

3 years ago

if the atmospheric pressure and temperature stay the same how would an increase in humidity affect takeoff performance

Mariulka [41]

High-density altitude and high humidity do not ever go hand in hand. If high humidity does exist, however, it exists wise to add 10 percent to your calculated takeoff distance and expect a reduced climb rate.

With a longer takeoff distance, the air exists less dense.

<h3>How do atmospheric temp pressure and rel humidity affects aircraft performance?</h3>

Several elements (altitude/pressure, temperature, and humidity) affect air density. A more elevated altitude, low-pressure area, higher temperature, and increased humidity all contain one effect: they lower the density of the air. And as a consequence of that: a decrease in aircraft and engine performance.

Humidity reduces the implementation of most aircraft, not only because of its effect on the wings but also effect on the engines. Humidity contains a significant effect on the path of plane flies. This exists due to the weight of the air when it exists in humid.

To learn more about humidity refer to:

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4 0

2 years ago