The tension in the rope when this bucket is suspended but stationery (static) is equal to 400 Newton.
<u>Given the following data:</u>
Mass = 40 kg.
<h3>How to calculate the tension?</h3>
Mathematically, the tension in the rope when this bucket is suspended but stationery (static) can be calculated by using this formula:
T = m(a + g)
<u>Note:</u> Acceleration due to gravity (g) is equal to 10 m/s² while the acceleration is 0 m/s² because the bucket is stationery (static)
Substituting the parameters into the formula, we have;
T = 40(0 + 10)
T = 400 Newton.
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Answer:
Midnight on the birthday. Hope this helps!
Answer:
F=989.6 N
Explanation:
Given that
Diameter of shaft = 70 mm
Diameter of bearing sleeve =70.2 mm
So clearance h=0.1 mm
Speed V= 400 mm/s
Length of shaft = 250 mm
We know that
μ= 900 x 0.005 Pa-s
μ= 4.5 Pa-s
As we know that
From Newton's law of viscosity ,the shear stress given as follows
We also know that
Force = shear stress x area
Now by putting the values
So force
F= 18,000 x π x 0.07 x 0.25
F=988.6 N