Answer:
77.2805 μF
Explanation:
Given data :
V = 2460 V
Q = 191 Kva
<u>Calculate the size of Each capacitor </u>
first step : calculate for the value of Xc
Q = V^2/ Xc
Xc ( capacitive reactance ) = V^2 / Q = 2460^2 / ( 191 * 10^3 ) = 31.683 Ω
Given that 1 / 2πFc = 31.683
∴ C ( size of each capacitor ) =
= 77.2805 μF
Image of wheel is missing, so i attached it.
Answer:
ω = 14.95 rad/s
Explanation:
We are given;
Mass of wheel; m = 20kg
T = 20 N
k_o = 0.3 m
Since the wheel starts from rest, T1 = 0.
The mass moment of inertia of the wheel about point O is;
I_o = m(k_o)²
I_o = 20 * (0.3)²
I_o = 1.8 kg.m²
So, T2 = ½•I_o•ω²
T2 = ½ × 1.8 × ω²
T2 = 0.9ω²
Looking at the image of the wheel, it's clear that only T does the work.
Thus, distance is;
s_t = θr
Since 4 revolutions,
s_t = 4(2π) × 0.4
s_t = 3.2π
So, Energy expended = Force x Distance
Wt = T x s_t = 20 × 3.2π = 64π J
Using principle of work-energy, we have;
T1 + W = T2
Plugging in the relevant values, we have;
0 + 64π = 0.9ω²
0.9ω² = 64π
ω² = 64π/0.9
ω = √64π/0.9
ω = 14.95 rad/s
Answer:
a) (option B) 230 kPa
b) (option A) 100 N/m
Explanation:
Given:
Diameter, d = 25 m
Thicknesses, t = 15 mm
Yield point = 240 MPa
Factor of safety = 2.5
a) To find the maximum internal pressure, let's use the formula:
Solving for P, we have:
P = 230.4 kPa
≈ 230 kPa
The maximum permissible internal pressure is nearly 230kPa
b) Given:
Thickness, t = 6.35 mm
L = 203 mm
Torque, T = 8 N m
Let's find the mean Area,
mA = (l - t)²
= (203 - 6.5)²
= 38671.22mm²
≈ 0.03867 m² (converted to meters)
To find the average shear flow, let's use the formula:
q = 103.4 N/m approximately 100N/m
The average shear force flow is most nearly 100 N/m
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Learn more about robot at:
brainly.com/question/10387419
Answer: I have answered the questions in rephrased sentences as below;
When implementing a safety and health program, management leadership need employee participation. Effective management of worker safety and health programs has improved employee productivity and morale in the workplace.
Nearly a third of all serious occupational injuries and illnesses stem from overexertion of repetitive motion.
Training is a way for employers to provide tools to enable employees to protect themselves and others from injuries.
Under OSHA, employees are protected from discrimination when reporting a work-related injury, illness, or fatality.
Explanation: All personnel including management & employees must be directly involved when workplace HSE policies are being made & reviewed. This is because everyone in the work environment is impacted one way or the other when incidents occur.
Training & Reporting are key responsibilities of managers, employers & supervisors, so it is mandatory to be done without discrimination so as to foster employees happiness which ultimately lead to zero incidents & increased productivity & profit.