Answer:
A. PMC tends to fit the construction purposes for which it was specifically designed.
Explanation:
took the test go it right
Answer:
Logarithmic decrement is equal to 0.182
Explanation:
given,
amplitude decay = 9 dB
number of cycles = 12 cycles
mass of the system = 7 kg
spring stiffness = 3000 N/m
logarithmic decrement = ?
now,
logarithmic decreament = 
= 
=ln (1.2)
= 0.182
Hence, Logarithmic decrement is equal to 0.182
Known :
V1 = 10 L
T1 = 27°C
P1 = 12 atm
P2 = 3 atm
Solution :
Work done in the process
W = P1 • V1 ln (P1 / P2)
W = (12 atm) • (10 L) ln (12 / 3)
W = 166.35 L • atm
W = 168.55 kJ
Answer:
True
Explanation:
True - because different classification of steel beam have different yield strength.
The moment capacity for a steel beam is given by;
M = Mn / Ωₙ
where;
M - the maximum moment acting on the beam
Ωₙ - is the Safety Factor for Elements in Bending = 1.67
Mn - nominal moment of the steel, given as

where;
Zₓ - the Plastic Section Modulus in the x or strong axis.
is the Yield Strength of the Steel (A36W, A46 W or A50W)
A36W = 36 ksi
A46 W = 46 ksi
A50W = 50 ksi
Thus, before you calculate the moment capacity for a steel beam, you have to determine the classification of beam, for the yield strength of the steel beam.
Answer:
C. 14.55
Explanation:
12 x 10 = 120
120 divded by 10 is 12
so now we do the left side
7 x 3 = 21 divded by 10 is 2
so now we have 14
and the remaning area is 0.55
so 14.55