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Serga [27]
3 years ago
8

How much faster does nitrogen monoxide (NO) effuse in comparison to dinitrogen tetraoxide (N2O4)?

Chemistry
1 answer:
juin [17]3 years ago
5 0

Answer:

N5O2

Explanation:

You might be interested in
a scuba diver's tank contains 0.29g of oxygen compressed into volume of 2.3L. What is the pressure in the tank at 9C?
viva [34]

Answer:

The answer to your question is P = 0.18 atm

Explanation:

Data

mass of O₂ = 0.29 g

Volume = 2.3 l

Pressure = ?

Temperature = 9°C

constant of ideal gases = 0.082 atm l/mol°K

Process

1.- Convert the mass of O₂ to moles

                16 g of O₂ -------------------- 1 mol

                0.29 g of O₂ ----------------   x

                    x = (0.29 x 1)/16

                    x = 0.29/16

                    x = 0.018 moles

2.- Convert the temperature to °K

Temperature = 9 + 273 = 282°K

3.- Use the ideal gas law ro find the answer

              PV = nRT

-Solve for P

              P = nRT/V

-Substitution

              P = (0.018 x 0.082 x 282) / 2.3

-Simplification

              P = 0.416/2.3

-Result

               P = 0.18 atm

5 0
3 years ago
Through which of the following processes is carbon directly transferred between living organisms and the environment?
sertanlavr [38]

Answer:

The answer is carbon cycle.

Explanation:

The carbon cycle is an important process for living organisms. As plants prepare their food through photosynthesis and is also an important source of fossil fuels for human activities.

Therefore carbon atoms are regenerated again and again in the carbon cycle process. This recycling process takes place between livings and nonliving things in the environment and also within the earth biosphere.

Abundance supply of carbon is necessary to carry out the biological processes. The entire carbon cycle is actually made up of sourced and sinks elements.

4 0
3 years ago
How many grams of Na2So4 would be formed if 0.75 moles of NaOH reacted?
Nata [24]

Answer:

\boxed{\text{53 g }}

Explanation:

You don't give the reaction, but we can get by just by balancing atoms of Na.

We know we will need the partially balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

M_r:                                 142.04  

             2NaOH + … ⟶ Na₂SO₄ + …  

n/mol:      0.75

1. Use the molar ratio of Na₂SO₄ to NaOH to calculate the moles of NaF.

Moles of Na₂SO₄ = 0.75 mol NaOH × (1 mol Na₂SO₄/2 mol NaOH

= 0.375 mol Na₂SO₄

2. Use the molar mass of Na₂SO₄ to calculate the mass of Na₂SO₄.

Mass of Na₂SO₄ = 0.375 mol Na₂SO₄ × (142.04 g Na₂SO₄/1 mol Na₂SO₄) = 53 g Na₂SO₄

The reaction produces \boxed{\text{53 g }} of Na₂SO₄.

4 0
3 years ago
Consider the single‑step, bimolecular reaction. CH3Br+NaOH⟶CH3OH+NaBr When the concentrations of CH3Br and NaOH are both 0.120 M
GarryVolchara [31]

Answer:

Explanation:

CH₃Br+NaOH⟶CH₃OH+NaBr

It is a single step bimolecular reaction so  order of reaction is 2 , one for CH₃Br and one for NaOH .

rate of reaction = k x [CH₃Br] [ NaOH]

.008 = k x .12 x .12

k = .55555

when concentration of CH₃Br is doubled

rate of reaction = .555555 x [.24] [ .12 ]

= .016 M/s

when concentration of NaOH  is halved

rate of reaction = .555555 x [.12] [ .06 ]

= .004  M/s

when concentration of both CH₃Br and Na OH is made 5 times

rate of reaction = .555555 x .6 x .6

= 0.2 M/s

8 0
3 years ago
What is the conjugate acid of HCO3- ?OH-H2CO3CO32-H2OH3O+
adell [148]

<u>Answer:</u> The conjugate acid of HCO_3^- is H_2CO_3

<u>Explanation:</u>

According to the Bronsted-Lowry conjugate acid-base theory:

  • An acid is defined as a substance which looses donates protons and thus forming conjugate base.
  • A base is defined as a substance which accepts protons and thus forming conjugate acid.

To form a conjugate acid of HCO_3^-, this compound will accept one proton to form H_2CO_3

The chemical equation for the formation of conjugate acid follows:

HCO_3^-+H^+\rightarrow H_2CO_3

The conjugate acid formed is named as carbonic acid.

Hence, the conjugate acid of HCO_3^- is H_2CO_3

5 0
4 years ago
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