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If a ball rolling down a hill is half way between the top and bottom, how much potential energy does the ball have compared to k

madreJ [45]

Answer:

The gravitational potential energy and kinetic energy of this ball should be equal (assuming that there is no energy loss due to friction.)

Explanation:

The ball loses gravitational potential energy as it rolls down the hill. At the same time, the speed of the ball increases, such that the ball gains kinetic energy.

If there is no friction on this ball (and that the ball did not deshape,) all the gravitational potential energy that this ball lost would be converted to kinetic energy.

If the gravitational field strength $g$ is constant throughout, the gravitational potential energy of an object in that gravitational field would be proportional to its height.

If $m$ denote the mass of this ball, the gravitational potential energy ( $\rm GPE$ ) of this ball at height $h$ would be ${\rm GPE} = (m \cdot g) \cdot h$ , which is proportional to $h\!$ .

The value of $g$ near the surface of the earth is indeed approximately constant (typically $g \approx 9.8\; \rm m \cdot s^{-2}$ .)

At halfway between the top and bottom of this hill, the height of this ball would be $(1/2)$ of its initial value (the value when the ball was at the top of the hill.) Because the $\rm GPE$ of this ball is proportional to its height, at halfway down the hill, the $\rm GPE\!$ of this ball would also be $(1/2)\!$ its initial value.

However, if there was no friction on this ball (and that the ball did not deshape,) that $(1/2)$ of the initial $\rm GPE\!$ of this ball was not lost. Rather, these $(1/2)\!$ of the initial $\rm GPE$ would have been converted to the kinetic energy ( $\rm KE$ ) of this ball.

Hence, when the ball is halfway down the hill:

$\displaystyle \text{GPE halfway down the hill} = \frac{1}{2}\, \text{Initial GPE}$ .

$\begin{aligned}& \text{KE halfway down the hill}\\ &= \text{Initial GPE} - \text{GPE halfway down the hill}\\ &= \text{Initial GPE} - \frac{1}{2}\, \text{initial GPE}\\ &= \frac{1}{2}\, \text{Initial GPE}\end{aligned}$ .

Therefore:

$\begin{aligned}& \text{GPE halfway down the hill} \\ &= \frac{1}{2}\, \text{Initial GPE} \\ &= \text{KE halfway down the hill}\end{aligned}$ .

In other words, under these assumptions, when this ball is halfway down the hill, the gravitational potential energy and the kinetic energy of this ball would be equal.

3 0

3 years ago

Electrons in __________ bonds remain localized between two atoms. electrons in __________ bonds can become delocalized between m

dsp73

Electrons in sigma <span>bonds remain localized between two atoms. Sigma </span><span>bond results from the formation of </span><span>a molecular orbital </span><span>by the end to </span><span>end overlap of atomic </span>orbitals. Electrons<span> in pi</span> bonds can become delocalized between more than two atoms. Pi bonds result from the formation of molecular orbital by side to side overlap of atomic orbitals.

7 0

3 years ago

How many grams of sodium carbonate are present after the reaction is complete?

mash [69]

Answer:

zero gram present after the reaction is completed

6 0

2 years ago

How to draw an.electron dot diagram. 1 write the chemical aymbo of the atom.2. Determine the number of valence electron the atom

almond37 [142]

Basically, an electron dot diagram is just a diagram showing the number of valence electrons a certain atom has (valence electrons are electrons in the outer-most electron level of an atom). The 5 steps they give you just tell you the order of where to put each dot. The picture I attached gives a better representation.

The number around the symbol shows the order of where you would put the dot. The 1 and the 2 on the top show that the first two dots go there, and the 3, 4, and 5 go around the rest of the sides. When it gets to 6, 7, and 8, the numbers go back around to fill in each side twice.

8 0

3 years ago

A student places three ice cubes in a beaker and allows them to partially melt. If she measures the temperature of the water in

Sonja [21]

<h2>Answers to the whole assignment:</h2>

**Check for proof photos at the bottom.**

**Answers are in bold.**

__________________________________________________________

A student places three ice cubes in a beaker and allows them to partially melt. If she measures the temperature of the water in the beaker, what will she most likely observe? Explain your answer.

She will see that the temperature of the water is 0 degrees Celsius and it stays at that temperature until all the ice cubes completely melt.

__________________________________________________________

Use the table on the right to calculate each required quantity. Record values to 3 significant digits.

First answer: 35.8 kJ

Second answer: 871 g

Third answer: Fe

__________________________________________________________

An iron sphere with a mass of 75.00 g is heated to a temperature of 385.0°C. It is then placed in a beaker containing 150.0 g H2O at 100.0°C.

First answer: 339 kJ

Second answer: 9.02 kJ

Third answer: No

__________________________________________________________

A sample of water has a mass of 100.0 g. Calculate the amount of heat required to change the sample from ice at –45.00°C to water vapor at 175.0°C. Relevant constant values are given to the right.

First answer: 325 kJ

Second answer: boiling the water

__________________________________________________________

Identify the correct description for each part labeled on the diagram.

A: ✔ heating solid

B: ✔ melting

C: ✔ heating liquid

D: ✔ boiling

E: ✔ heating gas

F: ✔ melting point

G: ✔ boiling point

Where are the particles closest together?

✔ A

<h2>Explanation:</h2>

When ice partially melts, the surrounding water remains at 0° Celsius. This is because ice melting only involves the water molecules overcoming intermolecular forces, or forces holding molecules together. The water molecules themselves aren't increasing in kinetic energy when turning into liquid. Since temperature measures kinetic energy, the temperature in this case, remains at 0°.

To find how much energy it takes to cause a phase change in a substance, you must find the number of moles, and determine whether to use ΔHvap and ΔHfus. ΔHvap is used to show how much energy is involved in evaporation and condensation, and ΔHfus is the same but used for melting and freezing. To find number of moles of a given substance, use the formula: mass of given substance divided by atomic mass. Both numbers have to use the same mass unit. Then, multiply number of moles by ΔHvap or ΔHfus to get kJ.

In a heating curve graph, the flat lines represent no change in energy, or the phase changes. The steep lines are change in energy, which are either heating or cooling. The bottom line is a heating/cooling solid. A heating/cooling solid is the coldest phase, which is why the line is at the bottom.

Here are photos of Edge to make things easier.

7 0

3 years ago