Yuppppp they are absolutely rightt
I believe the answer is B, as they only solely survive on tough and fibrous plant matter. Plants are producers because they can produce their own food instead of consuming something else to survive.
Answer:
1. 0.45 mole
2. 49.95g
Explanation:
The following were obtained from the question:
Volume of solution = 300mL = 300/1000 = 0.3L
Molarity = 1.5 M
Mole of CaCl2 =?
1. We can obtain the mole of the solute as follow:
Molarity = mole of solute /Volume of solution
1.5 = mole of solute/0.3
Mole of solute = 1.5 x 0.3
Mole of solute = 0.45 mole
2. The grams in 0.45 mole of CaCl2 can be obtained as follow:
Molar Mass of CaCl2 = 40 + (35.5 x 2) = 40 + 71 = 111g/mol
Mole of CaCl2 = 0.45 mole
Mass of CaCl2 =?
Mass = number of mole x molar Mass
Mass of CaCl2 = 0.45 x 111
Mass of CaCl2 = 49.95g
Density requires at least two things. In this case we would need volume of the object in addition to the mass. Density is equal to the mass divided by volume p = V/m
First, you will have to write out and balance the equation, so:
Because we’re looking at a single element reacting with an acid, we know that the reaction must be a single replacement.
Mg + HCl —-> MgCl2 + H2
We use H2, because hydrogen can only exist by itself when covalently bonded to itself, in a diatomic state.
Mg has an oxidation state of +2, while Cl has an oxidation state of -1. Therefore, you need 2 Cl to cancel the charge fully.
Now it needs to be balanced, so you get:
Mg + 2HCl —-> MgCl2 + H2
Now we have molar ratios to do our conversions
So we’ll use stoichiometry to find the theoretical yield for both reactants, and whichever one is the LEAST is the answer.
(32.5g Mg) (1mol/24.3g) (1mol MgCl2/1 mol Mg) (95.3g/1 mol MgCl2) = 127.5g
(32.5g HCl) (1mol/36.5) (1mol MgCl2/2mol HCl) (95.3g/1 mol MgCl2) = 42.4g
So, you will get 42.4 g of MgCl2
