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zimovet [89]
3 years ago
10

A cylinder has a height of 20 centimeters and a radius of 11 centimeters what is the volume

Mathematics
2 answers:
gulaghasi [49]3 years ago
7 0

Answer:

=7598.8 cm3

Step-by-step explanation:

3.14*11*11=379.94 cm2*20=7598.8 cm3

jeka943 years ago
4 0

Answer:

7602.65

Step-by-step explanation:

πrr

3.14...x 11 x 11 = 380.13271111

380.13271111 x 20 = 7602.65

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(Distribute , then simplify the remaining expression. Final answer must be in standard form) Please help !!
Sergeu [11.5K]
Problem 22
4x^2(2x^2+x-5) - x(x^3+5x^2-3) + 17
4x^2(2x^2)+4x^2(x)+4x^2(-5) - x(x^3)-x(5x^2)-x(-3) + 17
8x^4+4x^3-20x^2 - x^4-5x^3+3x + 17
7x^4-x^3-20x^2+3x + 17

So the final simplified answer to problem 22 is
7x^4-x^3-20x^2+3x + 17

--------------------------------

Problem 23
-2x(x^3-6x^2+6)+4x^3-(5x^4+10x)
-2x(x^3)-2x(-6x^2)-2x(6)+4x^3-(5x^4)-(10x)
-2x^4+12x^3-12x+4x^3-5x^4-10x
-7x^4+16x^3-22x

So problem 23 simplifies to
-7x^4+16x^3-22x

---------------------------------------------------------

Problem 24
4b[2a^2-5(3ab-2b^2)]+29ab^2
4b[2a^2-5(3ab)-5(-2b^2)]+29ab^2
4b[2a^2-15ab+10b^2]+29ab^2
4b[2a^2]+4b[-15ab]+4b[10b^2]+29ab^2
8a^2b-60ab^2+40b^3+29ab^2
8a^2b-31ab^2+40b^3

So problem 24 simplifies to 
8a^2b-31ab^2+40b^3

-------------------------------------------------

Problem 25
2y(6x-4x^2y)+13x^2y^2-6
2y(6x)+2y(-4x^2y)+13x^2y^2-6
12xy-8x^2y^2+13x^2y^2-6
12xy+5x^2y^2-6

The final answer for problem 25 is
12xy+5x^2y^2-6
8 0
3 years ago
What is the value for x?
konstantin123 [22]

Answer:

All angles must add up to 180, so if you add 69+5x+2+9y-3, it is = to 180.

First we can subtract 68 cancelling out 69, 2 and -3 so it is

5x+9y = 112. I assume this is an iscoceles triangle so we already knew 9y - 3 = 69, y=8, x=8

5 0
2 years ago
Factor the expression using the GCF.<br><br> 1. 9b+21<br> 2. 8x+2<br> 3. 14p-28<br><br> Thank You
Ira Lisetskai [31]

Answer:

the answer is 2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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JulsSmile [24]

Answer:

i beleive 9 times

Step-by-step explanation:

50÷5.50=9.09

3 0
2 years ago
HELP PLEASE. For parallelogram LMNO, if m∠L = 3x - 25 and m∠N = 2x - 10, find m∠M.
Dvinal [7]
In a parallelogram opposite angles are congruent, that means:

Angle L = Angle N, replace L & N by they respective value, then

3x-25 = 2x-10 ==> x=15 , Now plug the value of x in any of the 2 sides
3(15) -25 =20°

hence Angle L =- Angle N = 20°

Now let's calculate Angle M. In a parallelogram the adjacent angle are supplementary, that means their sum = 180°, then

Angle N + Angle N = 180°==> Angle M = 180°-20° = 160°
5 0
3 years ago
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