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erma4kov [3.2K]
3 years ago
14

Lifting a bale of cotton is no easy task. Farmer Jones wanted to store the cotton in the loft of his barn but he could not budge

the bale. He consulted the high school's science teacher for help. She suggested a simple machine.
Farmer Jones' options included an inclined plane, a fixed pulley, a block and tackle, and a lever. If he had to lift the bale of cotton to a height of fifteen feet, which would be the MOST practical solution?

A) lever
B) screw
C) inclined plane
D) block and tackle (pulley)
Physics
2 answers:
qwelly [4]3 years ago
8 0

Answer:

d

Explanation:

julia-pushkina [17]3 years ago
6 0
An inclined plane would not be practical because he would still have to push it and the amount of effort and energy would increase. A lever would not be practical because he would have to use his weight to make the bale rise 15 feet. He would also need to make sure that he has a 15 foot ladder in the first place. A screw would not be practical because he would have to drill a hole through the medium and use rotation.

A pulley would be the most practical way of moving the cotton bale. A pulley supports movement and will help the farmer move the bale.

\sf\ Answer:\ D)\ BLOCK\ AND\ TACKLE\ (PULLEY)
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Explanation:

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5) Find the initial velocity for a 700 kg car that
Serhud [2]

Answer:

Δv = 12 m/s, but we are not given the direction, so there are really an infinite number of potential solutions.

Maximum initial speed is 40.6 m/s

Minimum initial speed is 16.6 m/s

Explanation:

Assume this is a NET impulse so we can ignore friction.

An impulse results in a change of momentum

The impulse applied was

p = Ft = 1400(6.0) = 8400 N•s

p = mΔv

Δv = 8400 / 700 = 12 m/s

If the impulse was applied in the direction the car was already moving, the initial velocity was

vi = 28.6 - 12 = 16.6 m/s

if the impulse was applied in the direction opposite of the original velocity, the initial velocity was

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Other angles of Net force would result in various initial velocities.

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The velocity of a ball changes from ‹ 9, −6, 0 › m/s to ‹ 8.96, −6.12, 0 › m/s in 0.02 s, due to the gravitational attraction of
Alenkasestr [34]

Answer:

a) a=(-2,-6,0)m/s^2, with a magnitude of 6.3m/s^2

b) \frac{\Delta p}{\Delta t}=(-0.24,-0.72,0)Kgm/s^2, with a magnitude of 0.76Kgm/s^2

c) F=(-0.24,-0.72,0)N, with a magnitude of 0.76N

Explanation:

We have:

v_{ix}=9m/s, v_{iy}=-6m/s, v_{iz}=0m/s\\v_{fx}=8.96m/s, v_{fy}=-6.12m/s, v_{fz}=0m/s\\t=0.02s, m=0.12Kg

We can calculate each component of the acceleration using its definition a=\frac{\Delta v}{\Delta t}

a_x=\frac{v_{fx}-v_{ix}}{t} = \frac{(8.96m/s)-(9m/s)}{0.02s} =-2m/s^2\\a_y=\frac{v_{fy}-v_{iy}}{t} = \frac{(-6.12m/s)-(-6m/s)}{0.02s} =-6m/s^2\\a_y=\frac{v_{fz}-v_{iz}}{t} = \frac{(0m/s)-(0m/s)}{0.02s} =0m/s^2\\

The rate of change of momentum of the ball is \frac{\Delta p}{\Delta t} = \frac{\Delta mv}{\Delta t} = \frac{m\Delta v}{\Delta t} = ma

So for each coordinate:

\frac{\Delta p_x}{\Delta t}=-0.24Kgm/s^2\\\frac{\Delta p_y}{\Delta t}=-0.72Kgm/s^2\\\frac{\Delta p_z}{\Delta t}=0Kgm/s^2

And these are equal to the components of the net force since F=ma.

If magnitudes is what is asked:

a=\sqrt{a_x+a_y+a_z} =6.3m/s^2\\F=ma=\frac{\Delta p}{\Delta t}=0.76N

<em>(N and </em>Kgm/s^2<em> are the same unit).</em>

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