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erma4kov [3.2K]
3 years ago
14

Lifting a bale of cotton is no easy task. Farmer Jones wanted to store the cotton in the loft of his barn but he could not budge

the bale. He consulted the high school's science teacher for help. She suggested a simple machine.
Farmer Jones' options included an inclined plane, a fixed pulley, a block and tackle, and a lever. If he had to lift the bale of cotton to a height of fifteen feet, which would be the MOST practical solution?

A) lever
B) screw
C) inclined plane
D) block and tackle (pulley)
Physics
2 answers:
qwelly [4]3 years ago
8 0

Answer:

d

Explanation:

julia-pushkina [17]3 years ago
6 0
An inclined plane would not be practical because he would still have to push it and the amount of effort and energy would increase. A lever would not be practical because he would have to use his weight to make the bale rise 15 feet. He would also need to make sure that he has a 15 foot ladder in the first place. A screw would not be practical because he would have to drill a hole through the medium and use rotation.

A pulley would be the most practical way of moving the cotton bale. A pulley supports movement and will help the farmer move the bale.

\sf\ Answer:\ D)\ BLOCK\ AND\ TACKLE\ (PULLEY)
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The kenitc energy of the bullet lowers as it keeps going up.

Because gravity is pushing the bullet down as the bullet goes up.

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3 0
2 years ago
A driver notices an upcoming speed limit change from 45 mi/h (20 m/s) to 25 mi/h (11 m/s). If she estimates
zloy xaker [14]

Answer:

-2.79 m/s²

Explanation:

Given:

v₀ = 20 m/s

v = 11 m/s

Δx = 50 m

Find: a

v² = v₀² + 2aΔx

(11 m/s)² = (20 m/s)² + 2a (50 m)

a = -2.79 m/s²

Round as needed.

8 0
4 years ago
A car speeding down the highway honks its horn, which has a frequency 392 Hz, but a resting bystander hears the frequency 440 Hz
Natali [406]

Answer:

37.42 m/s

Explanation:

We know that apparent frequency, \bar f is given by

\bar f=f\frac {V}{V-V_s} where f is the given frequency in this case 392, V is the speed of sound in air which is given as 343 and V_s is the speed of car which is unknown, \bar f is given as 440 Hz

440=392\times \frac {343}{343-V_s}\\343-V_s=392\times \frac {343}{440}=305.5818182\\V_s=343-305.5818182=37.41818182\approx 37.42 m/s

8 0
3 years ago
Robert has just bought a new model roket, and is trying to measure its flight characteristics. The rocket engine package claims
rewona [7]
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4 years ago
I'm completely lost in physics, the Kinematics and dynamics units.. My exam is coming up.. If a biker travelling at 6.4m/s sees
Alexeev081 [22]
D=rt
when biker A catches biker B, the time they've been riding is the same, so 
t=t, or d/r=d/r
the rates are 6.4 and 4.7, so
d/6.4=d/4.7
biker B is 34m ahead, so 
(d+34)/6.4=d/4.7
multiply both sides by 6.4*4.7:
4.7(d+34)=6.4d
4.7d+=6.4d+159.8
1.7d=159.8
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Another way to think of it is that biker A gains 1.7 meters on B every second (6.4-4.7=1.5), so the time it'll take for him to gain 34 meters is 34/1.7=20 seconds. In that time, biker B travels 4.7*20=94 meters
8 0
3 years ago
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