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2 years ago

A bag has 2 blue marbles, 3 red marbles, and 5 white marbles. Which events have a probability greater than 5? Select three

Mathematics

1 answer:

Arturiano [62]2 years ago

8 0

Answer:

choosing 1 white marble replacing it, and then choosing another white one.

Step-by-step explanation:

there is 50% chance you pick any of the blue or red marbles, but you have a higher chance to pick another white one if the first one you chose was replaced.

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I need help on finding the next terms on this pls help

Katena32 [7]

Answer: -5, -7, and -9

Step-by-step explanation:

checking the pattern they are subtracting by two by the next term, so subtracting 2 from -3 would be -5 and so on.

4 0

3 years ago

What is pie exactly equal to?

natta225 [31]

Ummmm

pie = π

i think its right

3 0

3 years ago

Read 2 more answers

A french fry stand at the fair serves their fries in paper cones. The cones have a radius of 22 inches and a height of 66 inches

icang [17]

Answer:

The height of the new cones will be 16.5 inches.

Step-by-step explanation:

We know that,

The volume of a cone is,

$V=\frac{1}{3}\pi r^2 h$

Where, r is the radius of the cone,

h is the height of the cone,

In the original cone,

r = 22 inches,

h = 66 inches,

Thus, the volume would be,

$V_1=\frac{1}{3}\pi (22)^2(66)$

Also, for the new cone,

r = 44 inches,

Let H be the height,

So, the volume of the new cone would be,

$V_2=\frac{1}{3}\pi (44)^2(H)$

According to the question,

$V_2=V_1$

$\implies \frac{1}{3}\pi (44)^2(H)=\frac{1}{3}\pi (22)^2(66)$

$\implies H=\frac{22^2(66)}{44^2}=(\frac{22}{44})^2\times 66 = \frac{66}{4}=16.5$

Hence, the height of the new cones will be 16.5 inches.

7 0

2 years ago

A new screening test for Lyme disease is developed for use in the general population. The sensitivity and specificity of the new

Anit [1.1K]

Answer:

predictive value of a positive test = 18.18%

predictive value of a negative test = 94.03%

Step-by-step explanation:

Sensitivity = 60% = 0.6

Specificity = 70% = 0.7

Let True Positive = TP

True Negative = TN

False Negative = FN

$Sensitivity = \frac{TP}{TP + FN} \\0.6 = \frac{TP}{TP + FN} \\0.6TP + 0.6FN = TP\\0.4TP = 0.6FN\\TP = 1.5 FN$

$Specificity = \frac{TN}{TN + FP} \\0.7 = \frac{TN}{TN + FP} \\0.7TN + 0.7FP = TN\\0.7FP = 0.3 TN\\TN = 7/3 FP$

Prevalence = 10% = 0.1

Three hundred people are screened, $T_{total} = 300$

Total number of people having the disease, $T_{disease} = ?$

$Prevalence = \frac{T_{disease} }{T_{total} } \\0.1 = \frac{T_{disease} }{300 }\\T_{disease} = 30$

$T_{disease} = TP + FN\\30 = TP + FN$

But TP = 1.5 FN

30 = 1.5 FN + FN

30 = 2.5 FN

FN = 30/2.5

FN = 12

TP = 1.5 FN = 1.5 * 12

TP = 18

$FP + TN = T_{total} - T_{disease} \\FP + TN = 300 - 30\\FP + TN = 270\\FP + \frac{7}{3} FP = 270\\\frac{10}{3} FP = 270\\FP = 27 * 3\\FP = 81$

81 + TN = 270

TN = 189

To calculate the Predictive value of positive test (PPT)

$PPT = \frac{TP}{TP + FP} * 100\\PPT = \frac{18}{18+81} * 100\\PPT = \frac{18}{99} * 100\\PPT = 18.18 \%$

To calculate the Predictive value of negative test (PNT)

$PPT = \frac{TN}{FN + TN} * 100\\PPT = \frac{189}{189+12} * 100\\PPT = \frac{189}{201} * 100\\PPT = 94.03 \%$

7 0

2 years ago

Please help asap What is the sum of the following two polynomials?<br> (3x2 – 5x + 3) and (-x2 – 3x)

Anton [14]

(3x^2 - 5x +3) + (-2x -3x)
=3x^2-5x+3 + (6x^2)
=9x^2-5x+3

4 0

2 years ago

Read 2 more answers