Answer: they got 40 votes
Step-by-step explanation:
because 10+10+10+10 eqauls 40 yw friend follow me on tiktok @tayleerosee
Answer:
The arc length is 
Step-by-step explanation:
Given that,
The given curve between the specified points is

The points from
to 
We need to calculate the value of 
Using given equation

On differentiating w.r.to y




We need to calculate the arc length
Using formula of arc length

Put the value into the formula








Put the limits


Hence, The arc length is 
Answer:
x² - 30 + 5x
Step-by-step explanation:
(x + 5)(x − 5)
=x(x − 5)+5(x − 5)
=x² - 5 + 5x - 25
=x² - 30 + 5x
Answer:
Its the fourth one 1693000
Step-by-step explanation:
To get 1 you need to multiply -3/8 by -2/2/3 or -2.67