KE = (1/2)·(mass)·(speed)²
KE = (1/2)·(50 kg)·(18 m/s)²
KE = (25 kg)·(324 m²/s²)
KE = 8,100 kg-m²/s²
KE = 8,100 Joules
To solve this problem we will apply the concepts related to the conversion of units for which we will have that 1 slug is equal to 14.59kg. At the same time we will use Newton's second law for which weight is defined as the product between mass and acceleration (Due to gravity). This is then
A: Using the conversion ratio of slug to kilogram we have to,
Then
B: Using Newton's second law we have to,
Its is called intertidal zone
Explanation:
The earth rotation and the moon's pull of gravity causes the tides to rise and fall.High tides occur when the water advances to the furthers point of a shoreline where as low tides happen when the water recedes to the lowest point of the shoreline.Some kinds of animal and plants survive in the ecosystem present between the area of high tides and low tides refered to as the intertidal zone.This area is sometimes covered or uncovered by ocean waters.
Learn More
Intertidal zone:brainly.com/question/1346004
Keywords: area, shoreline, high tides, low tides.
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Answer:
1) F = 100N
2) a = 2 m/s²
3) m = 25 kg
Explanation:
1) F = ma ( F = ?, m = 10 kg, a = 10 m/s² )
F = 10×10
F = 100 N
2) F = ma ( F = 20N, m = 10 kg, a = ? )
20 = 10×a
10a = 20
a = 20/10
a = 2 m/s²
3)F = ma ( F = 100N, m = ?, a = 4 m/s² )
100 = m×4
4m = 100
m = 100/4
m = 25 kg
Hope that helps! Good luck!
Answer:
Explanation:
Given that
speed u=4×10⁶ m/s
electric field E=4×10² N/c
distance b/w the plates d=2 cm
basing on the concept of the electrostatices
now we find the acceleration b/w the plates
acceleration a=qE/m=1.6×10⁻¹⁹×4×10²/9.1×10⁻³¹=0.7×10¹⁴=7×10¹³ m/s
now we find the horizantal distance travelled by electrons hit the plates
horizantal distance X=u[2y/a]^1/2
=4×10⁶[2×2×10⁻²/7×10¹³]^1/2
=9.5cm
now we find the velocity f the electron strike the plate
v²-(4×10⁶)²=2×7×10¹³×2×10⁻²
v²=16×10¹²+28×10¹¹
v²=1.88×10¹³m/s
speed after hits =>V=4.34×10⁶ m/s
