Answer:
1.25 M
Explanation:
Step 1: Given data
Mass of KI (solute): 20.68 g
Volume of the solution: 100 mL (0.100 L)
Step 2: Calculate the moles of solute
The molar mass of KI is 166.00 g/mol.
20.68 g × 1 mol/166.00 g = 0.1246 mol
Step 3: Calculate the molar concentration of KI
Molarity is equal to the moles of solute divided by the liters of solution.
M = 0.1246 mol/0.100 L= 1.25 M
Answer:
Al + 3AgCl → AlCl₃ + 3Ag
Explanation:
The given equation is:
Al + AgCl →
We are to find the product and hence balance the equation. This problem is a simple single replacement reaction.
By virtue of this, Aluminum will displace Ag from the solution:
Al + AgCl → AlCl₃ + Ag
We then balance the equation:
Al + 3AgCl → AlCl₃ + 3Ag
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Answer:
Repulsive forces exist only when atoms are very close to each other. (3/14) "They [the atoms] will approach until both nuclei will simply shove each other because both of them are positive." The balance between the attraction and repulsion forces determines how close the atoms can get. The relationships between the magnitude and direction of repulsive and attractive forces. A stable state of a bond is when attractive forces balance repulsion forces. “A stable state between two atoms is when they attract each other with a force that equals the force that they repel each other.”
