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ella [17]
4 years ago
11

The reaction A2 + 2 B → 2 BA is thought to occur by the following mechanism:

Chemistry
1 answer:
adelina 88 [10]4 years ago
8 0

Answer:

c. Z is a catalyst, and ZA2 and A are reaction intermediates.

Explanation:

Overall reaction is given as;

A2 + 2 B → 2 BA

Mechanism:

Step 1: A2 + Z → ZA2

Step 2: ZA2 + B → BA + Z + A

Step 3: A + B → BA

The options given are centered upon catalysts and reaction intermediates. So before proceeding, we have to understand the difference between the two and how to identify them.

A catalyst is basically a reaction booster to speed up the rate of the reaction and the reaction intermediate is an unstable, temporl species formed from the reactants before getting to the products.

The difference is given as;

Catalysts are present as reactants in the very beginning and products at the end of the reaction.

Intermediates, on the other hand, are not present in the initial reaction but are produced within one of the steps and then consumed within another step.

Following the above, we can deduce that;

Z is a catalyst because it is present as a reactant in the beginning.

ZA2 and A are a reaction intermediates because they are not present in the overall reaction but are produced and consumed in one of the steps.

Correct option is given as;

c. Z is a catalyst, and ZA2 and A are reaction intermediates.

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Answer:

If the pKa of the acid is low (negative), then the acid is strong.

Explanation:

Ka, <em>the acid ionization constant,  </em>measures the strength of an acid in a solution. Stronger acids have higher Ka values.

We defined: pKa = -log[Ka]

This function is a decreasing function, meaning that pKa will be getting smaller and smaller,  while increasing Ka (high values of Ka will have negative pKa values). Therefore, stronger acids (high values of Ka), will have low (negative) pKa values.

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3 years ago
Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

Read more about rate constant

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2 years ago
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