Pure hydrogen (H₂) is a hazardous substance. Thus, safer and more cost effective techniques have been developed to store it as a
1 answer:
Answer: hello your question has some missing details attached below is the missing details
answer : 25.5% ( B )
Explanation:
<u>Determine percentage yield </u>
molar mass = 35 g/mol
mass of Li₃N(s) = 70 g
product LiH(s) = 8.0 g ( actual yield )
theoretical yield ( LiH ) = 4 * 7.95 = 31.8 g
percentage yield = actual yield * 100 / theoretical yield
= 8 * 100/31.8
= 25.5%
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Explanation:
It is known that for high concentration of , reduction will take place. As, cathode has a positive charge and it will be placed on left hand side.
Now, = 0 and the general reaction equation is as follows.
3.00 M n = 2 30 mM
E =
=
= 0.038 V
Therefore, we can conclude that voltage shown by the voltmeter is 0.038 V.