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Lena [83]
3 years ago
7

How many grams of nickel are in 1.57 moles of nickel

Chemistry
2 answers:
Crank3 years ago
8 0
Question: <span>How many grams of Nickel are in 1.57 moles of nickel

There are 58.6934 grams of Nickel in 1 mole. 

There are 92.1486 grams of Nickel in 1.57 moles.

Nickle is the most common ore to find on Earth. The atomic number of Nickle is 28 and the symbol for Nickle is Ni. The color is silvery-white with a tinge of gold.

Final Answer:
</span>
There are 92.1486 grams of Nickel in 1.57 moles.
monitta3 years ago
3 0

Answer:

92.1486

Explanation:

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What is the best explanation for why a particle is striking point X? When the dense, positive alpha particle passes close to a positive nucleus of gold, the alpha particle repels and hits the screen at point X.

Explanation:

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How would the addition of protons affect the concentration of CH3COOH? How would the addition of OH– affect the amount of CH3COO
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What mass of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution?
inna [77]

Answer:

459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution

Explanation:

Molarity is a measure of the concentration of a solute in a solution that indicates the amount of moles of solute that appear dissolved in one liter of the mixture. In other words, molarity is the number of moles of solute that are dissolved in a given volume.

The Molarity of a solution is determined by the following expression:

Molarity=\frac{number of moles of solute}{volume}

Molarity is expressed in units \frac{moles}{liter}

In this case:

  • Molarity: 1.56 M= 1.56 \frac{moles}{liter}
  • Number of moles of calcium chlorine= ?
  • Volume= 2.657 liters

Replacing:

1.56 M=\frac{Number of moles of calcium chlorine}{2.657 liters}

Solving:

Number of moles of calcium chlorine= 1.56 M* 2.657 liters

Number of moles of calcium chlorine= 4.14 moles

In other side, you know:

  • Ca: 40 g/mole
  • Cl: 35.45 g/mole

Then the molar mass of the calcium chloride CaCl₂ is:

CaCl₂= 40 g/mole + 2* 35.45 g/mole= 110.9 g/mole

Now it is possible to apply the following rule of three: if in 1 mole there is 110.9 g of CaCl₂, in 4.14 moles of the compound how much mass is there?

mass=\frac{4.14 moles*110.9g}{1 mole}

mass= 459.126 g

<u><em>459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution</em></u>

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