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Lena [83]
2 years ago
7

How many grams of nickel are in 1.57 moles of nickel

Chemistry
2 answers:
Crank2 years ago
8 0
Question: <span>How many grams of Nickel are in 1.57 moles of nickel

There are 58.6934 grams of Nickel in 1 mole. 

There are 92.1486 grams of Nickel in 1.57 moles.

Nickle is the most common ore to find on Earth. The atomic number of Nickle is 28 and the symbol for Nickle is Ni. The color is silvery-white with a tinge of gold.

Final Answer:
</span>
There are 92.1486 grams of Nickel in 1.57 moles.
monitta2 years ago
3 0

Answer:

92.1486

Explanation:

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A student has four resistors. Each resistor has a resistance of 100 ohms.
ValentinkaMS [17]

Answer:

The minimum resistance is 25 ohms.

Explanation:

Resistance of each resistor is 100 ohms. When resistors are connected in parallel, the equivalent resistance is lowest. For parallel combination, the equivalent resistance is given by :

\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+....

Here, all resistors are 100 ohms. So,

\dfrac{1}{R}=\dfrac{1}{100}+\dfrac{1}{100}+\dfrac{1}{100}+\dfrac{1}{100}\\\\R=25\ \Omega

So, the minimum resistance is 25 ohms.

7 0
3 years ago
What is the chemical formula of sodium azide?
Hunter-Best [27]
NaN₃ is the chemical formula for Sodium Azide
3 0
2 years ago
Sue dissolved a certain amount of salt in 400 grams of water to obtain 405 grams of salt solution. What was the mass of the salt
svp [43]
The answer would be 5 grams of salt
6 0
3 years ago
Read 2 more answers
In comparison to an atom of F-19 in the ground state, an atom of C-12 in the ground state has(1) three fewer neutrons
mel-nik [20]
(2) three fewer valence electrons is your answer.
6 0
2 years ago
How many bromine atoms are present in 37.9 g of CH2Br2?
VARVARA [1.3K]

Answer:

The answer to your question is: 6.55 x 10 ²³ atoms of Br

Explanation:

CH2Br2 = 37.9 g

MW CH2Br2 = (12 x 1) + (2 x 1) + (80 x 2) = 174 g

                   174 g of CH2Br2 ------------------  160 g of Br2

                   37.9 g of CH2Br2   ---------------     x

                x = 37.9 x 160/174 = 34.85 g of Br

                      1 mol of Br -----------------   160 g Br2

                         x              ----------------    174 g Be2

               x = 174 x 1 /160 = 1.088 mol of Br2

                1 mol of Br -----------------  6.023 x 10 ²³ atoms

            1.088 mol of Br -------------    x

                    x = 1.088 x 6.023 x 10 ²³ / 1 = 6.55 x 10 ²³ atoms

4 0
2 years ago
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