All categories

4 years ago

14. a? +b = cPythagorean Theorem

Mathematics

1 answer:

lions [1.4K]4 years ago

5 0

Answer:

a^2 + b^2 = c^2

Step-by-step explanation:

a^2 + b^2 = c^2

You might be interested in

Find the perimeter of following figure. 2 yd ,2yd ,5yd and 4 yd.

Gnesinka [82]

Answer:

13yd

Step-by-step explanation:

Perimeter is all the side lengths added

5 0

3 years ago

What is m = 2/3; (6, 1) in slope intercept form? :)

Marina86 [1]

Answer:

y = 2/3x - 3

Step-by-step explanation:

First let's look at what slope-intercept form is.

y = mx + b

m is the slope, which in this case is 2/3

b is the y-intercept, which we will find later.

Now that we have identified the parts of the equation, let's plug in what we know. Use the point given for your x and y values.

y = mx + b

1 = 2/3(6) + b

Let's simplify this to find b.

[multiply] 1 = 4 + b

[subtract 4]

-3 = b

We now have our b-value, which is also our y-intercept. Plug in this value into the standard slope-intercept equation.

y = 2/3x - 3

This is your equation.

Check this by plugging in the point again.

1 = 2/3(6) - 3

[multiply] 1 = 4 - 3

[subtract]

1 = 1

This expression is true; therefore, your answer is correct.

Hope this helps!

7 0

3 years ago

KIM [24]

Answer:

answer is in an image here

imageshare.best/image.php?id=JS9NDO

Explanation:

copy n paste in browser

not a bot btw

8 0

2 years ago

Read 2 more answers

Please somebody I need help

Goshia [24]

Answer:

Step-by-step explanation:

4 0

3 years ago

Pls show full working out

sweet-ann [11.9K]

Answer:

Question 1a. i) $x=1.8m$

Question 1a. ii) $Volume=27.6m^3$

Question 1b) $Volume=65.9m^3$

Explanation:

Question 1 a. i) Find the value of x.

$tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}$

For the smalll triangle you can write:

$tan(\theta )=\dfrac{x}{1m}$

For tthe big triangle:

$tan(\theta )=\dfrac{x+2.7m}{2.5m}$

Substitute:

$\dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}$

Solve for x:

$2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m$

Question 1a ii) Find the volume of the frustrum

Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

$Volume=(1/3)\pi \times radius^2\times height$

Substitute:

$Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3$

Find the volume of a cone with heigth = 1.8m and radius = 1m

$Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3$

Subtract the volume of the small cone from the volume of the big cone

$Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3$

Question 1b. Calculate the volume of the bin

i) Upper frustrum

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

ii) Lower frustrum

$\dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}$

$2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m$

$Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)$

$Volume=38.3m^3$

iii) Add the volume of the two frustrums

$Volume=27.6m^3+38.3m^3=65.9m^3$

6 0

3 years ago

14. a? +b = cPythagorean Theorem​

14. a? +b = cPythagorean Theorem