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Vitek1552 [10]
3 years ago
12

A 67.0 kg crate is being raised by means of a rope. Its upward acceleration is 3.50 m/s2. What is the force exerted by the rope

on the crate? A 67.0 kg crate is being raised by means of a rope. Its upward acceleration is 3.50 m/s2. What is the force exerted by the rope on the crate?
Physics
1 answer:
serious [3.7K]3 years ago
7 0
<span>A 67.0 kg crate is being raised by means of a rope. Its upward acceleration is 3.50 m/s2. What is the force exerted by the rope on the crate? 

</span>Newton's Second Law<span> of Motion states, “The force acting on an object is equal to the mass of that object times its acceleration.” We calculate as follows:
</span>
F = ma = 67.0 kg (3.50 m/s^2) = 234.5 J
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Will the waves be reflected with inversion or without? how do you know?
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3 years ago
A hose on the ground projects a water current upwards at an angle 40 to the horizontal at velocity 20 m/s find height at which w
irinina [24]

Answer:

<em>The water hits the wall at a height of 5.38 m</em>

Explanation:

<u>Projectile Motion </u>

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

The object describes a parabolic path given by the equation:

{\displaystyle y=\tan(\theta )\cdot x-{\frac {g}{2v_{0}^{2}\cos ^{2}\theta }}\cdot x^{2}}

Where:

y   = vertical displacement

x   = horizontal displacement

θ   = Elevation angle

vo = Initial speed

The hose projects a water current upwards at an angle of θ=40° at a speed vo=20 m/s.

The height at which the water hits a wall located at x=8 m from the hose is:

{\displaystyle y=\tan40^\circ\cdot 8-{\frac {9.8}{2*20^{2}\cos ^{2}40^\circ }}\cdot 8^{2}}

Calculating:

y = 5.38 m

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5 0
3 years ago
A baby carriage is sitting at the top of a hill that is 21 m high The carriage with the baby weighs 12 N
WITCHER [35]

Answer:E

=

252

J

Explanation:

The total mechanical energy of an object or system is given by:

E

m

e

c

h

=

K

+

U

Where

K

is the kinetic energy of the object and

U

is the potential energy of the object. The carriage, sitting motionless at the top of the hill, has only potential energy in the form of gravitational potential energy.

Gravitational potential energy is given by:

U

g

=

m

g

h

Where

m

is the mass of the object,

g

is the gravitational acceleration constant, and

h

is the height of the object above some specific reference point, in this case the ground

21

m

below.

The weight of a stationary object at the surface of the earth is equal to the force of gravity acting on the object.

W

=

→

F

g

=

m

g

We are given that the carriage weighs

12

N

, therefore

m

g

=

12

N

.

U

g

=

12

N

⋅

21

m

⇒

U

g

=

252

N

m

=

252

J

Answer link

Explanation:

5 0
3 years ago
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