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rjkz [21]
2 years ago
11

Jay fills a wagon with sand (about 20 kg) and pulls it with a rope 40 m along the beach. He holds the rope 25â above the horizon

tal. The rope exerts a 20-N tension force on the wagon. How much work does the rope do on the wagon?
Physics
1 answer:
never [62]2 years ago
8 0

Answer:

W = 725 J

Explanation:

given,

mass of wagon = 20 kg

distance of pull = 40 m

angle made with the horizontal = 25°

tension force on the wagon = 20 N

Work done = ?

Horizontal component of the force will help in movement of the wagon.

Horizontal component of force=

F_x = F cos θ

Work done is equal to force into displacement

W = F.s

W =  F cos θ.s

W = 20 cos 25° x 40

W = 725 J

hence, work done on pulling the wagon is equal to W = 725 J

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75kg man climbs a mountain 1000m high in 3hrs and uses 4100 joulse/min. (a) calculate the power consumption in watt, (b) what is
mr Goodwill [35]

Answer:

Explanation:

a) Power consumption is 4100 J/min / 60 s/min = 68.3 W(atts)

work done raised the potential energy

b) 75(9.8)(1000) / (3(3600)) = 68.055555... 68.1 W

c) efficiency is 68.1 / 68.3 = 0.99593... or nearly 100%

Not a very likely scenario.

3 0
2 years ago
An astronaut has a momentum of 280 kg and travels 10 m/s. what is the mass of the astronaut?
Kamila [148]

Answer:

The answer is

<h2>28 kg</h2>

Explanation:

The mass of an object given it's momentum and velocity / speed can be found by using the formula

m =  \frac{p}{v}  \\

where

m is the mass

p is the momentum

v is the speed or velocity

From the question

p = 280 kg/ms

v = 10 m/s

The mass of the object is

m =  \frac{280}{10}  = 28 \\

We have the final answer as

<h3>28 kg</h3>

Hope this helps you

3 0
3 years ago
The bowl now contains . Milliters of oil
Sergeeva-Olga [200]
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7 0
3 years ago
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The blades in a blender rotate at a rate of 6800 rpm . When the motor is turned off during operation, the blades slow to rest in
tangare [24]
The angular acceleration of the blade when it's switched off is (-6800 rev/min) divided by (2.8 sec) = -2,428.6 rev/(min-sec) = -40.5 rev/sec^2 .
5 0
2 years ago
A dentist causes the bit of a high-speed drill to accelerate from an angular speed of 1.72 x 10^4 rad/s to an angular speed of 5
Leto [7]

Answer:

The bit take to reach its maximum speed of 8,42 x10^4 rad/s in an amount of 1.097 seconds.

Explanation:

ω1= 1.72x10^4 rad/sec

ω2= 5.42x10^4 rad/sec

ωmax= 8.42x10^4 rad/sec

θ= 1.72x10^4 rad

\alpha = \frac{w2^{2}-w1^{2}  }{2*(\theta2 - \theta1)}

α=7.67 x10^4 rad/sec²

t= ωmax / α

t= 8.42 x10^4 rad/sec  /  7.67 x10^4 rad/sec²

t=1.097 sec

4 0
2 years ago
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