L = distance traveled.
The woman:
v₁ = the traveling speed
Time of travel, t₁ = l/v₁
The man:
v₁ + v₃ = the traveling speed.
Time of travel = l/(v₁ + v₂)
Answer:
The woman's time is l/v₁.
The man's time is l/(v₁ + v₂).
Explanation:
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(a) <u>The</u><u> </u><u>segment</u><u> </u>A shows acceleration as velocity increases with the increase in time.
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(b) <u>The</u><u> </u><u>segment</u><u> </u>C shows the object is slowing down as the time increases in segment C, the velocity decreases and afterwards it comes to rest.
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(c) The velocity is segment B is <u>4</u><u>0</u><u>m</u><u>/</u><u>s</u><u>.</u> And in the diagram there is no change in velocity.
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(d) The acceleration of segment B is <u>zero</u><u>.</u> As there in no change in curve and it is moving with uniform velocity.
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<h2>Thank you!</h2>
Answer:
the terminal velocity of 14 nested coffee filters is 3.2 m/s
Explanation:
Given the data in the question;
we know that;
The terminal velocity is proportional to the square root of weight.
v ∝ √W
v = k√W
the proportionality constant depends upon the surface area and the density of the medium (like air). The coffee filters can be stacked such that the resulting area is roughly unchanged. So, the constant of proportionality k is also unchanged
v/√W = constant
v₂/√W₂ = v₁/√W₁
v₂ = v₁√(W₂ / W₁ )
given that;
v₁ = 0.856 m/s,
W₂ = 14W₁; meaning 14 coffee filters have 14 times the weight of a single coffee filter
so we substitute
v₂ = 0.856 √(14W₁ / W₁ )
v₂ = 0.856 √( 14( W₁/W₁)
v₂ = 0.856 √( 14(1)
v₂ = 0.856 √( 14 )
v₂ = 0.856 × 3.741657
v₂ = 3.2 m/s
Therefore, the terminal velocity of 14 nested coffee filters is 3.2 m/s
Answer:
C
Explanation:
got a one hundred on the test
The answer is a rainforest I’m pretty sure
