Answer
From
V=Distance/time
The distance round a circular path or Object is 2πr
so
v=2πr/T
Making T(period) subject
T=2πr/v
where v is the linear velocity.
We don't have the velocity but we can get it.
The Moon and Earth exert gravitational force on each other and the Moon is kept in Orbit by Centripetal force.
Since the Moon doesn't fly out of Orbit... it must mean that the Gravitational force being exerted on it by the Earth is equal to its centripetal Force.
Equating Both (Fg=Fc)
Fg=GMm/R²
Fc=mv²/r
GMm/R² = mv²/R
Canceling out "m" and "r" on both sides
we're left with
V²=GM/R
V=√GM/R
Where M= Mass of Earth (5.98x10^24)
R=Distance between the center of earth and the Moon
G= Gravitational Constant(Value 6.67x10^-11)
V=√6.67x10^-11 x 5.98x10^24/(3.82x10^8)
V=1021.84meters per second.
Now
T=2πr/v
=2π x 3.82x10^8 / 1021.84
T=2.35x10^6seconds
Converting to days by dividing by(24 x 3600)
You have
T=27.2days approx.
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The cooling find are there to keep the temperature low. They are mostly black in color, and hence, radiate heat, which is how the temperature is controlled.
So in calculating this one its is really hard to explain how i get it on solve it but you must consider this factors that i give in getting the answer. First is the distance cover by the ball when it is hit by the club, Second is you must estimate both of those data when it is in the moon and in the earth whre the gravity of the earth is 9.8m/s^2 so by calculating the Gravity of the moon or gMoon is equal 1.74m/s^2
From the question, The kinetic energy of the fired arrow is equal to the work done by the bale of hale in stopping the arrow.
We make use of the following formula
mv²/2 = F'd................... Equation 1
Where
- m = mass of the arrow
- v = velocity of the arrow
- F' = average stopping force acting on the arrow
- d = distance of penetration
Make F' the subject of the equation
F' = mv²/2d.................. Equation 2
From the question,
Given:
- m = 20 g = 0.02 kg
- v = 60 m/s
- d = 40 cm = 0.4 m
Substitute these values into equation 2
Hence, The average stopping force acting on the arrow is 90 N
Learn more about average stooping force here: brainly.com/question/13370981
Answer:
Transverse
Explanation:
There are two types of waves, according to the direction of their oscillation:
- Transverse waves: in a transverse wave, the direction of the oscillation is perpendicular to the direction of motion of the wave. Examples of transverse waves are electromagnetic waves
- Longitudinal waves: in a longitudinal wave, the direction of the oscillation is parallel to the direction of motion of the wave. Examples of longitudinal waves are sound waves.
Light waves corresponds to the visible part of the electromagnetic spectrum, which includes all the different types of electromagnetic waves (which consist of oscillations of electric and magnetic fields that are perpendicular to the direction of propagation of the wave): therefore, they are transverse waves.
