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zimovet [89]
3 years ago
9

1. Compare and Contrast microwaves with visible light using wavelength, frequency and energy

Physics
1 answer:
coldgirl [10]3 years ago
4 0
Visible light has more energy than microwaves but it has a smaller wavelength than microwave
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A 12-kg projectile is launched with an initial vertical speed of 20 m/s. It rises to a maximum height of 18 m above the launch p
kirill115 [55]

Answer:

Change in mechanical energy, \Delta E=283.2\ J

Explanation:

It is given that,

Mass of the projectile, m = 12 kg

Speed of the projectile, v = 20 m/s

Maximum height, h = 18 m

Initially, the projectile have only kinetic energy. it is given by :

K=\dfrac{1}{2}mv^2

K=\dfrac{1}{2}\times 12\ kg\times (20\ m/s)^2

K = 2400 J

Finally, it have only potential energy. it is given by :

P = mgh

P=12\ kg\times 9.8\ m/s^2\times 18\ m

P =2116.8 J

The change in mechanical energy is given by :

\Delta E=K-P

\Delta E=2400-2116.8

\Delta E=283.2\ J

So, the change in mechanical energy is 283.2 J. Hence, this is the required solution.

8 0
3 years ago
To meet the productivity goal, you must move 75 units of product per hour. You have moved 30 units of product in 30 minutes. How
9966 [12]

Answer:

1.5 unit of product per min

Explanation:

30 units of product was moved in 30 minutes.

Number of units left = Total number of units-number of units moved

                                =75-30 =45 units

45 units is available to be moved for the rest 30 min. To be able to achieve this goal of 75 units of product per hour.

45/30 amount of units must be moved in 1 min

=1.5 unit per min

4 0
3 years ago
Two charged particles are located on the x axis. The first is a charge 1Q at x 5 2a. The second is an unknown charge located at
sergejj [24]

Answer:

Q_2 = +/- 295.75*Q

Explanation:

Given:

- The charge of the first particle Q_1 = +Q

- The second charge = Q_2

- The position of first charge x_1 = 2a

- The position of the second charge x_2 = 13a

- The net Electric Field produced at origin is E_net = 2kQ / a^2

Find:

Explain how many values are possible for the unknown charge and find the possible values.

Solution:

- The Electric Field due to a charge is given by:

                               E = k*Q / r^2

Where, k: Coulomb's Constant

            Q: The charge of particle

            r: The distance from source

- The Electric Field due to charge 1:

                               E_1 = k*Q_1 / r^2

                               E_1 = k*Q / (2*a)^2

                               E_1 = k*Q / 4*a^2

- The Electric Field due to charge 2:

                               E_2 = k*Q_2 / r^2

                               E_2 = k*Q_2 / (13*a)^2

                               E_2 = +/- k*Q_2 / 169*a^2

- The two possible values of charge Q_2 can either be + or -. The Net Electric Field can be given as:

                               E_net = E_1 + E_2

                               2kQ / a^2 = k*Q_1 / 4*a^2 +/- k*Q_2 / 169*a^2

- The two equations are as follows:

        1:                   2kQ / a^2 = k*Q / 4*a^2 + k*Q_2 / 169*a^2

                               2Q = Q / 4 + Q_2 / 169

                               Q_2 = 295.75*Q

        2:                    2kQ / a^2 = k*Q / 4*a^2 - k*Q_2 / 169*a^2

                               2Q = Q / 4 - Q_2 / 169

                               Q_2 = -295.75*Q

- The two possible values corresponds to positive and negative charge Q_2.

7 0
3 years ago
Name 3 elements in group one
Vinil7 [7]

Answer:

I don't really understand the question but fire water air and like earth but you said 3

Explanation:

7 0
3 years ago
What is the middle layer of earth called
irinina [24]
The middle or centre of the Earth is the core. However the middle of the layers from the surface to the centre of the Earth is known as mantle. 
6 0
3 years ago
Read 2 more answers
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