1. Area of the right angled ∆ = 1/2 × base × height
height = 16m
base = √20² – 16²
= √400 –256
= √144
= 12 m
Area of the unshaded portion
= 1/2 × base × height
= 1/2 × 12 × 16
= 96m²
2. Area of the rectangle = 300ft × 150ft
= 45000sq. ft
Area of the shaded portion = 100² + (1/2×b×h)
= 10000 + (1/2×120×150)
= 10000 + 9000
= 19000 sq. ft
Area of the unshaded part of the rectangle
= (45000 – 19000)sq. ft
= 26000 sq. ft
Hi there friend, your answer for perimeter is 18.
I’ve included a graph below to help explain why but basically if you count the squares, each side measures 4 1/2 units so if you multiply 4 1/2 units by 4(the number of sides) you get 18.
OK so on the top problem, the first thing you want to do is find the √37, once you know the answer to that you can compare it to 5 1/4 then it will be much easier to see is in fact √37 less than 5 1/4 or not.
On the bottom you want to know if 15 over the square root of ten is greater than 8.38 so what you want to do is to first find the square root of ten. after you know this then you put that number under 15. then you can compare what ever 15÷√10 is to 8.83. if you need any more info let me know.