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Rudiy27
3 years ago
12

-6x -6= help pls i don’t understand

Mathematics
1 answer:
makkiz [27]3 years ago
8 0

The answer here is x=-1

                                             Explanation

___________________________________________________________

-6x -6 = 0

-6x - 6 +6 = 0+6

-6x = 6

-6x/-6 = 6/-6

x = -1

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Express 194720 in standard form correct to 3 significant figures<br>​
ELEN [110]

Answer:

1.95 x 10^5

Step-by-step explanation:

First look at the 4th digit in the number 194720 as the the question said to round to 3 significant figures. If the 4th digit is more than 5, then add 1 to the third digit which results in 195000. Now the question also said to express in standard form. Look for the first non-digit number in 195000. After 1 put a decimal point and remove all the zeros after the point which results in 1.95. Now count how many digits you moved to the left which comes as 5. Write the answer as 1.95 x 10^5.

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Svetlanka [38]
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7 0
3 years ago
National data indicates that​ 35% of households own a desktop computer. In a random sample of 570​ households, 40% owned a deskt
Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a​ desktop.

Step-by-step explanation:

We are given that National data indicates that​ 35% of households own a desktop computer.

In a random sample of 570​ households, 40% owned a desktop computer.

<em><u>Let p = population proportion of households who own a desktop computer</u></em>

SO, Null Hypothesis, H_0 : p = 25%   {means that 35% of households own a desktop computer}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 570​ households who owned a desktop computer = 40%

            n = sample of households = 570

So, <u><em>test statistics</em></u>  =  \frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }

                               =  2.437

<em>Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.</em>

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0
3 years ago
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